1. The problem statement, all variables and given/known data A thin rod of length 1.4m and mass .2kg is suspended freely from one end. It is pulled to one side and then allowed to swing like a pendulum, passing through its lowest position with angular speed 7.84 rad/s. Neglecting friction and air resistance, find how far above that position the center of mass rises. m = .2 kg l = 1.4 m max angular velocity = 7.84 rad/s I've figured out: moment of inertia = .130666 max kinetic energy = 4.0157 J 2. Relevant equations Work = integral of the torque from (theta-0 to theta-max) tourqe = rF*sin(theta) = rmg*sin(theta) tourqe = I(angular acceleration) 3. The attempt at a solution I've tried integrating both tourqe equations above as well as integrating the second one subtracted from the first one. But i usually end up with something like: sin(theta) = a number larger than 1 I think I am just integrating the wrong thing. I know this could probably be done with the conservation of engergy, but when I try that, I end up with a height that is greater than the lengh of the rod. Thanks for any help!