Max Memory Space Addressed by 18 Address Bits

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The largest memory space that can be addressed by 18 addressing bits is...


Is there a formula for this perhaps?
 
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How many different combinations of 18 ones and zeros are there?

- Warren
 
2^n
n=18

2^18= 262,144
 
Would that be 262,144 bytes then
 
Assuming that each "memory location" holds one byte, yes.
 
Thanks for the help?
 
Something to note - while you might be able to have addresses going all the way up to 2^18 a lot of chips do not have memory locations for all of the addresses. Such as variants in the PIC16F8X range.
 
I noticed in a Digital Circuits book that with 18 address leads it should be 256K. So where does my 262,144 come from with 2^18. Just a thought?
 
256 * 1,024 = 262,144. The "k" in this context means 1,024, not 1,000.

- Warren