Max Temp in Ideal Gas Transformation: 2490K

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SUMMARY

The forum discussion centers on calculating the maximum temperature (Tmax) of an ideal gas undergoing a transformation defined by the equation p = p0 - aV, where p0 is 10^5 Pa and a = 10^6/8.3 Pa/m³. The maximum temperature options provided include 2450 K, 2500 K, 2480 K, 2490 K, and 2460 K. The correct approach involves substituting pressure into the ideal gas law equation (pV/T = constant) to derive Tmax as a function of volume (V). It is noted that the number of moles of gas is necessary for a definitive numerical solution.

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  • Understanding of the ideal gas law (pV/T = constant)
  • Familiarity with thermodynamic transformations
  • Knowledge of pressure-volume relationships in gases
  • Basic algebra for solving equations
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  • Study the derivation of the ideal gas law and its applications
  • Learn about thermodynamic processes and transformations
  • Explore how to substitute variables in equations to find maxima
  • Research the significance of the number of moles in gas calculations
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Students studying thermodynamics, physics educators, and anyone interested in the properties and behaviors of ideal gases during transformations.

KingAntikrist
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Again, it's a translation, i don't know if it's 100% accurate in english

Homework Statement



An ideal gas suffers a transformation under the law p=p_0-aV, p_0=10^5 Pa, a=\frac{10^6}{8,3} \frac{Pa}{m^3}. The maximum temperature on this transformation is: ...

A) 2450 K
B) 2500 K
C) can't be calculated (THIS IS NOT THE ANSWER)
D) 2480 K
E) 2490 K
F) 2460 K

Homework Equations



\frac{pV}{T}= ct

The Attempt at a Solution



The attempt? Nill...not even my physics teacher could solve this (private lesson with him). And i really don't have any ideea...

That aV is actually another pressure...
 
Last edited:
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Substitute p(V) from the equation to the ideal gas equation to obtain T(V). For V>0, find max(T) :smile:

EDIT: I think the number of moles of the gas must be given for a numerical value of Tmax.
 
Last edited:

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