Max Torque for Steel Torsion Bar - Calculate Now

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SUMMARY

The maximum torque that can be safely applied to a cylindrical steel torsion bar with a diameter of 20mm and an allowable shear stress of 200 MPa is calculated using the formula τ = Tr / J. The modulus of elasticity (E = 209 GPa) is not required for this calculation, as it pertains to stress and geometry rather than elasticity. The shear modulus (G) would be necessary only if calculating the rotation of the bar under torque.

PREREQUISITES
  • Understanding of shear stress and its calculation
  • Familiarity with the formula τ = Tr / J
  • Knowledge of torsion bar geometry
  • Basic concepts of material properties, specifically shear modulus
NEXT STEPS
  • Research the calculation of the second polar moment of area (J) for cylindrical sections
  • Learn about the relationship between shear stress and torque in torsion bars
  • Explore the significance of shear modulus (G) in material deformation
  • Investigate applications of torsion bars in engineering design
USEFUL FOR

Mechanical engineers, materials scientists, and students studying torsion mechanics will benefit from this discussion, particularly those involved in the design and analysis of torsion bars and related components.

2slowtogofast
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A cylindrical torsion bar made of steel (E = 209 GPa) with diameter of 20mm. The allowable shear stress for this material is 200 MPa what is the max torque that can be safely applied to this bar.

\tau = Tr / J

\tau = shear stress
T = torque
r = radius
J= second polar moment of area

I was thinking of using this formula but I would not have used E = 209GPa in my solution is this wrong? If so could somebody point me in the right direction.
 
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You are correct, you don't need E; the max torque is a function of the max stress and the geometry of the section. It is not related to the elasticity modulus. You would need the shear modulus G if you wanted to calculate the amount of rotation, not the stress.
 
thanks
 

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