Max Velocity for Car to Turn Over When Skidding Sideways

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SUMMARY

The maximum velocity at which an idealized cube-shaped car (with a side length of 2 meters) can skid sideways and just begin to turn over is determined by analyzing the work done by its weight during rotation about the contact point with the curb. The work-energy theorem is applied, specifically using the integral W = ∫ τ_weight dθ, to calculate the work done and ascertain if the angle exceeds 45 degrees. Initial calculations were incorrect, highlighting the importance of accurate application of physics principles in this scenario.

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  • Concept of torque and its application in physics
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marsm
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Homework Statement



An idealised car (meaning: a cube with a = 2m) skids sideways toward a curb (height of the curb doesn't matter). At which maximum velocity v must it skid to just about turn over?

Sorry, but the forum didn't generate the TeX for me, so here it is on mathbin.net:

http://www.mathbin.net/11540
 
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The weight of the car does work while it is rotating about the contact point with the curb. This means that the rotational speed will decrease as it turns over. The work done by it will also change during the rotation. So you have to use

[tex]W = \int \tau _{weight} \ d\theta[/tex]

to calculate the work done and check if the angle is more that fourty five degrees (work-energy theorem).
 
Last edited:
Thank you very much, andrevdh, that was a great help!

My initial calculation was quite wrong, obviously.
 

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