Maximizing Flow Rate in a Water Pipe: Accounting for Pipe Losses

  • Context: Archived 
  • Thread starter Thread starter soronemus
  • Start date Start date
  • Tags Tags
    Flow Max Pipe
Click For Summary
SUMMARY

The maximum flow rate in a water pipe supplied with city water at 50 psi pressure can be calculated using Bernoulli's principle, but ignoring pipe losses leads to inaccuracies. The discussion highlights the necessity of accounting for viscous drag and the limitations of Bernoulli's equation when pipe losses are neglected. The Darcy-Weisbach equation is recommended for a more accurate assessment, but requires knowledge of pipe length and Reynolds number. The solution emphasizes the importance of determining whether the flow is laminar or turbulent to apply the correct calculations.

PREREQUISITES
  • Understanding of Bernoulli's principle
  • Familiarity with the Darcy-Weisbach equation
  • Knowledge of flow types: laminar and turbulent
  • Basic concepts of fluid dynamics and pressure differentials
NEXT STEPS
  • Study the Darcy-Weisbach equation for calculating head loss in pipes
  • Learn how to determine the Reynolds number for flow characterization
  • Explore laminar flow velocity profiles and their implications on flow rate
  • Investigate the effects of pipe diameter and length on flow rate and pressure loss
USEFUL FOR

Engineers, fluid dynamics students, and professionals involved in plumbing design or hydraulic systems who need to optimize water flow rates in piping systems.

soronemus
Messages
13
Reaction score
0

Homework Statement



What is the maximum flow rate that can be seen in a water pipe where city water is supplied to a building. The pressure behind the water is 50psi, and the inner diameter of the pipe is 2".


Homework Equations


bernoulli's principle


The Attempt at a Solution



I am more over verifying that my process is correct in solving this. I assumed no pipe losses. I used the bernoulli equation. The first point of the bernoulli equation I estimated as the surface of a pond, ocean, or some infinite water source where v=0 (the water elevation does not change) to cancel out the velocity term for point 1. The pressure on top of the surface is 50psi.

The elevation for both points I assumed to be equal, which cancels out all terms for point 1 other than P/density.

For point 2 I used the exit of the pipe where the fed water is first exposed to the atmosphere (p=0). Since the elevation is the same this leaves only the following equation:

Pressure_1/density=V_2^2/2
V=Q/A
therefore
Pressure/density=(Q/A)^2/2
The only unknown in this equation is Q, so it can be solved for.

My question is: is this a valid solution if I am ignoring pipe losses?
 
Physics news on Phys.org
In a pipe of constant cross section, a pressure difference between the ends implies a force difference, yet the flow rate must be constant. This proves the question is all about viscous drag and Bernoulli does not help.
 
You can't use Bernoulli, and I will show you why:

Create a balance between the ends of the pipes, 1 designating the front of the pipe and 2 designating the end.

You will have:
P1,T1,V1,rho1,Z1 and P2,T2,V2,rho2,Z2

You know that the temperature, density, and elevation are constant, so T2=T1, rho1=rho2 and Z2=Z1.

You can now apply the Bernoulli equation.

(P2-P1) - rho/2 (V2^2 - V1^2) + hl = 0

Immediately we have a problem. While we do know P2 - P1, we don't know V2 or V1. Additionally, if we wish to apply the Darcy friction/loss formulas (see: https://en.wikipedia.org/wiki/Darcy–Weisbach_equation) we do not know the length of the pipe or the operating Reynolds number, so we can't use these equations.

My recommendation:
Assume the flow is laminar. You know there is a certain velocity profile from laminar flow. From here you can calculate the flow rate using Q = V*A where V is the average velocity and A is the cross sectional area. You can do this if the flow is turbulent too, but you have to make some additional assumptions.
 

Similar threads

  • · Replies 13 ·
Replies
13
Views
1K
  • · Replies 16 ·
Replies
16
Views
3K
Replies
12
Views
2K
Replies
1
Views
2K
Replies
2
Views
2K
Replies
3
Views
2K
Replies
7
Views
3K
  • · Replies 8 ·
Replies
8
Views
4K
Replies
5
Views
2K