Maximizing Projectile Distance: Calculation at 45 Degrees

clipperdude21
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When you kick a ball of mass m into the air at a speed v0 at an angle theta to the ground, how do you know that the maximum distance in the x direction that the ball can travel occurs at 45 degrees.

Can someone show me the calculation of how this happens?
 
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The formula for the range, [tex]R[/tex], of a projectile has a term

[tex]\sin(2\alpha)[/tex]

where [tex]\alpha[/tex] is the launch angle above the horizon. This means that the range will be a maximum when the projectile is launched such that

[tex]2\alpha = 90^o[/tex]
 
thanks! how did u get that equation. is it possible to derive it from the kinematics equations? THanks!

nvm i think i did it
 
Last edited:

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