Maximizing Seed Germination: Calculating Probability without Binomial Theorem

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SUMMARY

The probability of a certain type of seed germinating is 0.8, and in a pack of 100 seeds, the probability that at least 75% will germinate can be calculated using the normal distribution approximation instead of the binomial theorem. The mean (\u03bc) is calculated as np, which equals 80, and the standard deviation (\u03c3) is calculated as the square root of np(1-p), resulting in approximately 4. The "half-integer correction" is applied, interpreting "at least 75%" as 74.5 or larger for accurate probability assessment.

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A certain type of seed has a probability of 0.8 of germinating. In a pack of 100 seeds, what is the probability that at least 75% will germinate?




Solution can be achieved on a calculator using binomial theorem. Is there any other way of doing it without using binomial theorem ?
 
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You could use the normal distribution approximation, with "half- integer correction".

A binomial distribution in which the probability of a single success is p, repeated n times, has mean \mu= np and standard deviation \sigma= \sqrt{np(1-p)}. If n is large, the normal distribution with the same mean and standard deviation is a good approximation.

Since a normal distribution allows real number values while a binomial distribution requires integers, you interpret any real number that rounds to a particular integer as being that integer. Here, "at least 75%" or "at least 75 out of 100" would be equivalent to "74.5 or larger". That's the "half integer correction".
 

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