Maximizing the height of a bullet in cylindrical coordinates

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Qbit42
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Homework Statement


A gun can fire shells in any direction with the same speed v0. Ignoring air resistance and using cylindrical polar coordinates with the gun at the origin and z measure vertically up, show that the gun can hit any object inside the surface

z = [tex]\frac{v_{0}^{2}}{2g}[/tex] - [tex]\frac{g\rho^{2}}{2v_{0}^{2}}[/tex]


Homework Equations



[tex]\phi[/tex] is fixed so any derivative terms can be neglected, making Newtons equations:

F[tex]_{\rho}[/tex] = m[tex]\frac{d^{2}\rho}{dt^{2}}[/tex]

F[tex]_{z}[/tex] = m[tex]\frac{d^{2}z}{dt^{2}}[/tex]


The Attempt at a Solution



I know how I should tackle this problem, but I can't get started. I want to use Newton's laws to solve for z(t) and [tex]\rho[/tex](t). Differentiate z(t) to solve for max height at t[tex]_{final}[/tex]. Then solve [tex]\rho[/tex](t[tex]_{final}[/tex]) for t[tex]_{final}[/tex]([tex]\rho[/tex]) and use that to find z([tex]\rho[/tex]).

I have no idea how to solve Newtons equations in this case, it seems like F[tex]_{z}[/tex] = F[tex]_{g}[/tex] and I have no idea what expression to use for F [tex]_{\rho}[/tex]

Edit: I do not know why my subscripts are being interpreted as superscripts but I can't get it to stop.
 
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Without getting into too much detail, the subscript/superscript thing is because of a feature of the browser layout. Don't mix LaTeX code with regular letters; it's better to put the entire equation or expression in LaTeX.

[tex]F_\rho = m\frac{\mathrm{d}^2\rho}{\mathrm{d}t^2}[/tex]

and [itex]z(t)[/itex] etc.

Anyway: you've correctly identified that the force in the z (vertical) direction is the force of gravity. What is the net force acting in the ρ (horizontal) direction? This part of the problem is simple projectile motion, except that the coordinates are labeled ρ and z instead of x and y as you might be used to.

Once you've found the functions [itex]z(t)[/itex] and [itex]\rho(t)[/itex], you will need to combine them to find [itex]z(\rho)[/itex], and then differentiate - but not to find the max height. You should instead be looking at the direct 3D distance between the projectile and the launch point.
 
Thanks for the clarification on the superscript problem. I honestly have no idea what force would be acting on the bullet in the horizontal direction, its been a long time since I've done any classical mechanics and I always hated it (still do).

As to the differentiation part, If I have z([tex]\rho[/tex]) then I guess I'd want to differentiate with respect to [tex]\rho[/tex] or [tex]\phi[/tex] to maximize 3D distance.

Edit: Do I have to split the initial velocity into components based on angle between [tex]\rho[/tex] and z? Like [tex]V_{oz}[/tex] = [tex]V_{0}[/tex]Sin([tex]\theta[/tex]) and [tex]V_{o\rho}[/tex] = [tex]V_{0}[/tex]Cos([tex]\theta[/tex]). Although I don't see how that would help since I need an expression for the time derivative of [tex]V_{0}[/tex] and those are just constants.
 
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