Maximum Acelleration of a System of Masses

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SUMMARY

The discussion focuses on the maximum acceleration of a system of masses connected by a pulley, specifically comparing scenarios with a 1kg mass and a 100kg mass. The calculated accelerations are 0.099 m/s² when the 1kg mass hangs and 9.9 m/s² when the 100kg mass hangs. This indicates that the maximum acceleration of the system approaches free-fall acceleration when the larger mass is in the hanging position. The analysis emphasizes the importance of understanding the forces acting on each mass and the impact of mass distribution on acceleration.

PREREQUISITES
  • Understanding of Newton's second law (a = F/m)
  • Knowledge of gravitational force (Fg = mg)
  • Familiarity with free body diagrams
  • Basic principles of pulleys and tension in strings
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  • Study the effects of mass distribution on acceleration in pulley systems
  • Learn about free body diagram construction for complex systems
  • Investigate the role of friction in pulley systems
  • Explore real-world applications of Newton's laws in mechanical systems
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liuquinlin
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Homework Statement


A mass on a horizontal friction-free air track is accelerated by a string attached to another 10kg mass hanging vertically from a pulley. Suppose the masses described are 1kg and 100kg. Compare the acellerations when the masses are interchanged, that is, for the case when the 1kg mass dangles over the pulley and then the case where the 100kg mass dangles over the pulley. What does this indicate about the maximum acceleration of such a system of masses?


Homework Equations


Fg=mg
a=f/m

The Attempt at a Solution


I found the two acellerations (.099m/s^2 and 9.9m/s^2 respectively). However I do not understand what they mean by maximum acceleration or what the two acellerations indicate.
 
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liuquinlin said:

Homework Statement


A mass on a horizontal friction-free air track is accelerated by a string attached to another 10kg mass hanging vertically from a pulley. Suppose the masses described are 1kg and 100kg. Compare the acellerations when the masses are interchanged, that is, for the case when the 1kg mass dangles over the pulley and then the case where the 100kg mass dangles over the pulley. What does this indicate about the maximum acceleration of such a system of masses?


Homework Equations


Fg=mg
a=f/m

The Attempt at a Solution


I found the two acellerations (.099m/s^2 and 9.9m/s^2 respectively). However I do not understand what they mean by maximum acceleration or what the two acellerations indicate.

It will be easier if the pulley is frictionless. I guess I will assume it is ...

Can you draw a picture of each mass and the forces on each and then the net force on each mass (free body diagram)? If you can then you can make some mathematical statements that include a (acceleration). You know the two masses and g... all that's left is a... You might use T to signify tension since each mass will have this "force" as the masses are attached to each other.

Do this with the 100 kg mass on the horizontal plane and the 1 kg mass (hanging) and accelerating which way?

Then reverse the two masses. It should be obvious that the accelerations will be very different. So you did the above using g=10 m/s/s and now you see that one situation is very close to that and the other situation is a lot less than that? (If you used 9.8 for g you did something wrong). Hint one situation is close to freefall acceleration but not quite there...
 
That 9.9m/sec^2 value looks awful close to a well known acceleration value of an object subject to a certain force on Planet Earth. Hint: If the mass on the table is close to zero and the hanging mass is much greater than zero, what's the acceleration of the system?
 
Ohhh, I understand now. Thanks!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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