What Are the Maximum and Minimum Values of y When x^3 is 8+- 2(14)^1/2?

Thread starter Liang Wei
Start date Jun 21, 2014
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Maximum Minimum

In summary: I am not sure what I am supposed to do.x^3=15.84+-5.84yIn summary, at x= 15.84, y has a local minimum value.

Jun 21, 2014

Liang Wei

Ok thanks

<h2>1. What is the maximum value of y?</h2><p>The maximum value of y is 12 when x is 8 + 2(14)^1/2.</p><h2>2. What is the minimum value of y?</h2><p>The minimum value of y is -12 when x is 8 - 2(14)^1/2.</p><h2>3. How do you calculate the maximum and minimum values of y?</h2><p>The maximum and minimum values of y can be calculated by plugging in the given value of x into the equation y = x^3 and solving for y.</p><h2>4. Can the maximum and minimum values of y be negative?</h2><p>Yes, the maximum and minimum values of y can be negative depending on the value of x. In this case, the maximum value of y is positive while the minimum value of y is negative.</p><h2>5. Is there a specific range for the values of x in this equation?</h2><p>No, there is no specific range for the values of x in this equation. As long as x is a real number, the equation will have a maximum and minimum value for y.</p>

1. What is the maximum value of y?

The maximum value of y is 12 when x is 8 + 2(14)^1/2.

2. What is the minimum value of y?

The minimum value of y is -12 when x is 8 - 2(14)^1/2.

3. How do you calculate the maximum and minimum values of y?

The maximum and minimum values of y can be calculated by plugging in the given value of x into the equation y = x^3 and solving for y.

4. Can the maximum and minimum values of y be negative?

Yes, the maximum and minimum values of y can be negative depending on the value of x. In this case, the maximum value of y is positive while the minimum value of y is negative.

5. Is there a specific range for the values of x in this equation?

No, there is no specific range for the values of x in this equation. As long as x is a real number, the equation will have a maximum and minimum value for y.