Maximum Deflection Angle In Elastic Collision

AI Thread Summary
The discussion centers on deriving the maximum deflection angle in elastic collisions using the equation v1i + v1f = 2v, where v1i and v1f represent the initial and final velocities of mass m1, respectively. The participants clarify that this equation is valid only for components of velocity normal to the contact plane and emphasize the importance of considering momentum conservation in two dimensions. They suggest taking the x-axis along the direction of motion of mass m1 for analysis. Additionally, using LaTeX for equation representation is recommended to enhance clarity in communication. The conversation highlights the need for a deeper understanding of the collision dynamics to progress further.
vibha_ganji
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Homework Statement
Show that, in the case of an elastic collision of a particle of
mass m1 with a particle of mass m2 , initially at rest, (a) the
maximum angle m through which m1 can be deflected by the
collision is given by cos^2(theta) = 1 - (m2/m1)^2 so that
0 is less than or equal to theta which is less than or equal to pi/2 and when when m1 < m2.
Relevant Equations
v1f = ((m1-m2)/(m1+m2))*(v1i)
v of center of mass reference frame = (m1v1i + m2v2i)/(m1+m2)
I started by writing the equation v1i + v1f = 2v and then drawing a triangle with v1i, v1f, and 2v as the three sides. Then I used the Law of Cosines to solve for cos theta but this did not lead to a solution. Could I have a hint on how to begin? Thank you!
 
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vibha_ganji said:
I started by writing the equation v1i + v1f = 2v
Why? How are you defining those variables, and by what reasoning do you get that equation?
 
The variable v1i is the initial velocity of mass m1 in the laboratory frame and v1f is the final velocity of mass m1 in the laboratory frame.The variable v is the difference in velocity between the center of mass frame and the laboratory frame. Therefore, we can write that the initial velocity of mass m1 in the center of mass reference frame is v1i’ = v1i - v. Similarly, we can write that v1f’ = v1f - v. Since it is an elastic collision, v1i’ is the negation of v1f’. We can substitute-(v1i-v) for v1f’ and write it as -v1i+v = v1f - v. This can be simplified to v1i + v1f = 2v.
 
vibha_ganji said:
Since it is an elastic collision, v1i’ is the negation of v1f’.
No, that is only true for the components of velocity normal to the contact plane.
Notice that since m2 is initially stationary v1i and v are parallel. Your equation leads to v1f also being parallel to these.
 
Oh ok that makes more sense! Could I have a hint on how to continue?
 
vibha_ganji said:
Oh ok that makes more sense! Could I have a hint on how to continue?
The next step is to consider that this collision is two-dimensional and conserve momentum in two mutually perpendicular directions. The usual convention is to take the x-axis along the direction of motion of the projectile mass m1.

An auxiliary step would be for you to learn how to use LaTeX and use it to write your equations. It will make your equations easier to read and our advice easier to give.
 
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