Maximum flame temperature during Combustion of CH4

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SUMMARY

The maximum flame temperature during the combustion of methane (CH4) in pure oxygen is calculated to be 4805K. The error in the initial calculation stemmed from a misapplication of the temperature equation, specifically using (Tf - 298)² instead of the correct (Tf² - 298²). Additionally, the heat capacity of nitrogen (N2) was provided for a different combustion scenario involving 20% O2 and 80% N2, which is not applicable to the pure oxygen combustion case. The calculated flame temperature for the latter scenario is 2280K.

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Homework Statement
Combustion of CH4 at constant pressure (P=1bar).
Relevant Equations
CH4 (g) + 2O2 (g) --> CO2 (g) + 2H2O (g)
Enthalpy of reaction = -803 kJ.mol-1
Hi, I have to calculate the maximum flame temperature of the reaction above. The answer is 4805K but I didn't manage to obtain that answer. Please help me find my error, thank you so much! The values of C are below the solution attempt.
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What does a flame that you can see consist of?
 
Where you have written (Tf - 298)2, that should be (Tf2 - 2982). Correcting this gives 4805 K. But who says this is the right answer? Why do you think they give you the heat capacity of N2?
 
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mjc123 said:
Where you have written (Tf - 298)2, that should be (Tf2 - 2982). Correcting this gives 4805 K. But who says this is the right answer? Why do you think they give you the heat capacity of N2?
Thank you sir! My excuses for my math. They gave the heat capacity of N2 for the following question that asks about the combustion in 20% O2 and 80% N2.
This question is for combustion in 100% O2.
But again, thank you so much for your help!
By the way, I found 2280K for the combustion in 20% O2 and 80% N2, that should be correct right?
 

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