Maximum Helium Fraction: Neutron Decay Time & Rest Mass Difference

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SUMMARY

The maximum Helium fraction, Yp, can be determined using a neutron decay time of 89 seconds and a rest mass difference, Qn, of 0.129 MeV. The discussion clarifies that a free neutron decays into a proton, electron, and antineutrino, resulting in hydrogen. However, if the neutron decays within a tritium atom, it can transform into Helium-3 (He-3). The context of the decay process is crucial for accurately calculating Yp.

PREREQUISITES
  • Understanding of neutron decay processes
  • Familiarity with particle physics terminology
  • Knowledge of Helium isotopes, specifically He-3
  • Basic concepts of mass-energy equivalence
NEXT STEPS
  • Research neutron decay mechanisms and their implications in cosmology
  • Study the formation and properties of Helium-3
  • Explore the role of tritium in nuclear reactions
  • Learn about mass-energy equivalence and its applications in particle physics
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Students and researchers in nuclear physics, astrophysics enthusiasts, and anyone interested in the processes of nucleosynthesis and particle decay.

bolahab
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Suppose the neutron decay time n was 89 sec. AND the difference in
rest mass between neutron to proton, Qn, was 0.129 MeV. What would
the maximum Helium fraction, Yp, be?
 
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bolahab said:
Suppose the neutron decay time n was 89 sec. AND the difference in
rest mass between neutron to proton, Qn, was 0.129 MeV. What would
the maximum Helium fraction, Yp, be?
One needs to provide more information in order to solve this problem. A free neutron decays into a proton, electron and antineutrino, so the product of free neutron decay would be hydrogen. Or is the neutron decaying in a tritium atom, which then is transformed to He-3?

Or does one mean hydrogen rather than He?
 
yes it is transformed into He-3, that was all the info from the question, but the rest info as it says in the book when it is transformed into He-3
 

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