Maximum shear stress in square tubing

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SUMMARY

The maximum shear stress in square tubing occurs at the neutral axis, as confirmed by user bigislander72. The equation for calculating this stress is τ_max = 0.75(V/t)[b^3 - (b - 2*t)^3]/[b^4 - (b - 2*t)^4], where V represents the transverse shear force, b is the outside width of the square tube, and t is the wall thickness. This formula is applicable under the assumption of sharp corners, effectively ignoring the impact of rounded corners.

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  • Understanding of shear stress concepts
  • Familiarity with square tubing geometry
  • Knowledge of transverse shear force calculations
  • Basic proficiency in mechanics of materials
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Mechanical engineers, structural engineers, and students studying mechanics of materials will benefit from this discussion, particularly those focused on analyzing shear stress in square tubing applications.

bigislander72
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Does anyone have the equation for this. I tried one from my textbook, and the answer I get is less than the average shear stress which is impossible. So I was curious to look at onother version, because perhaps the eq. has a typo? Also, does it occur at the neutral axis like it would in a round shaft? I thought I remebered my prof. say not, but I am out of school now; don't have those resources anymore!
 
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bigislander72: Yes, the maximum shear stress occurs at the square tube neutral axis, and is tau_max = 0.75(V/t)[b^3 - (b - 2*t)^3]/[b^4 - (b - 2*t)^4], where V = transverse shear force on cross section, b = square tube outside width, and t = wall thickness. This formula assumes sharp corners, or ignores rounded corners, which is a close enough approximation.
 

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