Maximum speed of a cylinder dropped on a spring

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Homework Help Overview

The problem involves a cylinder dropped onto a spring, focusing on the maximum compression of the spring, the spring deflection at maximum velocity, and the maximum velocity of the cylinder. The context is rooted in energy conservation principles, specifically relating gravitational potential energy, kinetic energy, and elastic potential energy.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to equate gravitational potential energy to kinetic energy to find the maximum velocity. They express uncertainty about when the cylinder's speed is at its maximum in relation to spring deflection.

Discussion Status

Participants are engaging in clarifying the original poster's approach and questioning the completeness of their reasoning. There is an exploration of the relationship between energy forms and the timing of maximum speed in the context of the problem.

Contextual Notes

The original poster indicates a discrepancy between their calculated maximum velocity and the expected answer, suggesting a potential misunderstanding of the problem setup or energy conservation principles.

Rajveer97
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Homework Statement


Cylinder A (mass = 5kg) is released from rest at a height h =100mm above a spring of stiffness k = 1.8 kN/m. Determine, (i) the maximum compression of the spring, (ii) the spring deflection when the cylinder’s velocity is a maximum, and, (iii) the maximum velocity of the cylinder

I just need to confirm part iii

Homework Equations


Ep=mgh
Ek=(1/2)mv^2
Es=(1/2)kx^2
F=kx

The Attempt at a Solution


For part (i) I got 0.106
(ii) 27.2mm
For (iii) I did Ep=Ek which gave me v=1.4. The correct answer is supposed to be 1.49, I feel my answer is similar is wrong but similar just by chance. I just don't fully understand the question, when will the speed be maximum, before or after deflection? I feel before but I'm unsure.

Thanks
 
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Hi,
You don't really specify what you did. Could there be a term missing in your 'doing'?
 
BvU said:
Hi,
You don't really specify what you did. Could there be a term missing in your 'doing'?
Well I meant I basically made gravitational potential energy equal kinetic energy and solved for v
 
Es ?
 
Rajveer97 said:
I did Ep=Ek
What, roughly, is the cylinder's acceleration very shortly after hitting the spring?
 

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