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## Homework Statement

If the maximum tension that a cable can safely withstand is 9000N and the maximum upward acceleration of the elevator is 1.00 ms

^{2}, how many 80kg passengers may be safely carried in the elevator?

(The mass of the cable is negligible)

## Homework Equations

F=ma

T=mg

## The Attempt at a Solution

If I let a

_{y}=1.00 ms

^{2}and F=9000N then I have:

9000N = m * a

_{y}and m = 9000. The number of 80kg people the elevator can withstand is 9000 / 80 = 112 people.

Is this correct?