(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

If the maximum tension that a cable can safely withstand is 9000N and the maximum upward acceleration of the elevator is 1.00 ms^{2}, how many 80kg passengers may be safely carried in the elevator?

(The mass of the cable is negligible)

2. Relevant equations

F=ma

T=mg

3. The attempt at a solution

If I let a_{y}=1.00 ms^{2}and F=9000N then I have:

9000N = m * a_{y}and m = 9000. The number of 80kg people the elevator can withstand is 9000 / 80 = 112 people.

Is this correct?

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# Homework Help: Maximum tension a cable can withstand.

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