MHB Maximum Value of Square Root Expression with Three Variables in [0,1]

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The discussion focuses on finding the maximum value of the expression √|x-y| + √|y-z| + √|z-x| for variables x, y, and z constrained within the interval [0, 1]. The original poster mentions being unwell due to chicken pox, which has delayed their participation. They express disappointment that no one responded to the previous week's problem of the week (POTW). A suggested solution is provided, although specific details of the solution are not included in the summary. The thread highlights both a mathematical challenge and the personal circumstances of the poster.
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Here is this week's POTW:

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Let $x,\,y,\,z\in [0,\,1]$. Find the maximum value of $\sqrt{|x-y|}+\sqrt{|y-z|}+\sqrt{|z-x|}$.

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Hi MHB, I have been feeling so sick for the past few days (due to chicken pox) and even now, I just couldn't sit but have to lie down most of the time.

Therefore any activities involving me in this forum will be delayed until I feel much better.
 
Hi MHB! I am back, even though I am not fully recovered yet, but, I am back. (Nod)

Unfortunately, no one answered last two week's POTW.(Sadface) You can read the suggested solution of other as follows:
We may assume $0\le x \le y \le z \le 1$. Then we let

$M=\sqrt{y-x}+\sqrt{z-y}+\sqrt{z-x}$

Since $\sqrt{y-x}+\sqrt{z-y}\le \sqrt{2[(y-x)+(z-y)]}=\sqrt{2(z-x)}$, we have

$M\le \sqrt{2(z-x)}+\sqrt{z-x}=(\sqrt{2}+1)\sqrt{z-x}\le \sqrt{2}+1$

The equality holds if and only if $y-x=z-y,\,x=0, z=1,\,y=\dfrac{1}{2}$.

Hence, $\sqrt{|x-y|}+\sqrt{|y-z|}+\sqrt{|z-x|}\le \sqrt{2}+1$.
 
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