Maximum Volume of an Open Top Box

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The discussion revolves around finding the maximum volume of an open-top box defined by the equations L = 50 - 2x, W = 40 - 2x, and height x. The volume is expressed as V = 4x³ - 180x² + 2000x, and the user seeks an alternative method to solve for maximum volume without using derivatives or graphing. Participants clarify that while derivatives are a common approach, they are not strictly necessary for solving the problem. The conversation emphasizes understanding the problem rather than adhering to a specific method. The focus remains on exploring different techniques for maximizing the volume.
Carl_M
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Homework Statement


Is there another way to do this question?
Is this right?

L = 50-2x
W = 40-2x
Height= X

Homework Equations



//

V=L x W x H
V= (50-2x)(40-2x)(x)
V= (2000 -180x +4x²)(x)
V= 2000x -180x² +4x³
V= 4x³ - 180x² +2000x
V' = 12x² -360x +2000
X = (360 (+/-)sqrt(360²-4(12)(2000))) / 2(12)
X = 7.36...

How would I do this without using f ' ( x ) ? nor graph it

The Attempt at a Solution

 
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Are they asking you to do it without taking the derivative and setting it equal to zero?
Graphing is never necessary. Just for convenience.
 
No, but how would I do that?

It's not required or anything nor is it asked.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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