Maximum weight a bar and cables can hold before breaking

[SteamKing]

So I am finding all the forces from the moments first then applying those to the force equations?

No, you use the one moment equation I indicated,

ΣMz = F_AB(12) - F_AC(18.46) = 0 to find F_AB in terms of F_AC

Then, you can substitute F_AB back into the force equations to find the other forces in terms of W.

 

[Alison A.]

No, you use the one moment equation I indicated,

ΣMz = F_AB(12) - F_AC(18.46) = 0 to find F_AB in terms of F_AC

Then, you can substitute F_AB back into the force equations to find the other forces in terms of W.

Alright I found F_AB to be (4615/5539)W and F_AC to be (3000/5539)W

 

[Alison A.]

Alright I found F_AB to be (4615/5539)W and F_AC to be (3000/5539)W

And from there force equations I found F_OA to be -0.6983W

 

[Alison A.]

WOOOOOOOOOOOOOO I got the right answer. Wow that was a lot of work, I think I've gone through about 10 pages of paper. Thank you so much for sticking with me even when it seemed like I couldn't grasp the most simple concepts . Could you help me find the last part to my other problem you've been answering? That is my last problem... then I'm finally done.