What Is the Maximum Weight a Flowerpot Can Be Supported By Two Cables?

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SUMMARY

The maximum weight of a flowerpot supported by two cables, AB and AC, is determined by the tension limits of each cable, which is set at 50 lb. Cable AB makes a 60-degree angle with the horizontal, while cable AC makes a 53.1-degree angle. The analysis shows that the cable with the greater angle from the horizontal (cable AB) must bear a greater tension than the cable with the smaller angle (cable AC), leading to the conclusion that cable AC will reach its tension limit first. Therefore, the maximum weight is constrained by the tension in cable AC.

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Homework Statement


Determine the maximum weight of the flowerpot that can be supported without exceeding a cable tension of 50 lb in either cable AB or AC. Note that the 2 cables make an angle 60 and 53.1 respectively with the horizontal


Homework Equations



Fnet=ma


The Attempt at a Solution


Fxnet=TABcos60-TACcos53.1 =0
Fynet-TABsin60+TACsin53.1-W=0
I don't know how to figure out if 50lb is the tension in cable AB or in AC
 
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i worked out the problem by trial and error and found out that the more vertical cable has the tension of 50 why is this so?
 
myoplex11 said:
i worked out the problem by trial and error and found out that the more vertical cable has the tension of 50 why is this so?
You have determined that the x components of the 2 tensions must be equal. A little trig will tell you why the cable with the greater angle from the horizontal must have a greater tension than the cable with the smaller angle, and thus, must fail first.
 

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