Maxiumum Incident power on solar cell ?

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Discussion Overview

The discussion revolves around determining the maximum incident power on a dual junction solar cell, specifically focusing on the calculation of total incident solar power (Pin) necessary for efficiency evaluation. The context includes simulation results and the impact of environmental conditions on solar power input.

Discussion Character

  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant simulated a dual junction solar cell and seeks the exact value of incident solar power (Pin) for their specific structure parameters.
  • Another participant states that the power of sunlight at ground level is approximately 1000 W/m², which is the standard reference value for testing PV cells.
  • A different participant reiterates the 1000 W/m² figure and notes that actual power input can vary significantly based on local conditions, suggesting the use of a light meter for precise measurements.
  • One participant shares their experience of calculating efficiency using 100 mW/cm² but found a lower actual value of 50 mW/cm² during morning hours in their location.
  • Another participant emphasizes that the actual irradiation value is influenced by various factors such as weather conditions, time of day, and geographical location.

Areas of Agreement / Disagreement

Participants agree on the standard reference value of 1000 W/m² for solar power input, but there is disagreement regarding the actual incident power that can be expected in different conditions, with multiple views on how to measure and interpret these values.

Contextual Notes

Participants highlight that the actual incident power can differ from the standard reference due to environmental factors, and they express uncertainty about the precise conditions affecting their measurements.

spoonfeeder
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Hi
I have simulated a dual junction(Multijunction) solar cell of thickness 10 microns and length 20 microns in silvaco atlas device simulator. In order to calculate its efficiency i need exact value of incident solar power i.e Pin for the above said structure.

These are the parameters obtained from IV graph:
Isc=9.25A
Voc=1.32V
Pmax=9.828W
FF=0.80
To find out efficiency i need Pin(Total Incident solar power) for the mentioned structure length and thickness.
 
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The power of sunlight at the ground level, when all the (mean) atmospheric dissipations and reflections have been detracted, is very close to 1000 W/m2 (outside the atmosphere it's value is 1367 W/m2 at the mean distance Sun-Earth).

1000 W/m2 is also the standard reference value used for testing and certification of PV cells.
 
Daiquiri said:
The power of sunlight at the ground level, when all the (mean) atmospheric dissipations and reflections have been detracted, is very close to 1000 W/m2 (outside the atmosphere it's value is 1367 W/m2 at the mean distance Sun-Earth).

1000 W/m2 is also the standard reference value used for testing and certification of PV cells.

Pin = 1000W/m2 = 100mW/cm2 = 645mW/in2
.
is generally accepted power input on a solar cell, which occurs under certain optimum conditions. In practical situation the value differs from day to day and even from hour to hour. The best way to find the exact input power at certain time is to use a 'light meter'.

I once calculated the efficiency using 100mW/cm2, then when I used a light meter to verify the number, I found power in the AM hours in my area (south-eastern USA) actually is 50mW/cm2.
 
Neandethal00 said:
I once calculated the efficiency using 100mW/cm2, then when I used a light meter to verify the number, I found power in the AM hours in my area (south-eastern USA) actually is 50mW/cm2.

1000 w/m2 is the standard value of irradiation, used for certification and comparison of PV cells - which is the case here, if I understood it well.

For example, see this tech sheet of a Sharp 167 W module: http://www.abcsolar.com/pdf/sharp167.pdf - the bottom of the page 2, where it reads "standard test conditions".

Then of course, the actual value of irradiation will strongly depend on the local (geographical) weather conditions, like clouds, air humidity, air pollution, period of the year, morning, noon or evening... etc.

A bit like when we say that the air density is 1.225 kg/m3. It is a standard reference value valid for dry air at 15 °C and 101325 Pa of air pressure, but as soon as one of these conditions change, the value of density will change too.

Cheers!
 

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