- #1

- 15

- 0

You should upgrade or use an alternative browser.

- Thread starter Matt Smith
- Start date

In summary, Maxwell's equations are valid in all (inertial) reference frames. This is a result of special relativity.f

- #1

- 15

- 0

- #2

Mentor

- 36,492

- 13,607

- #3

Mentor

- 34,516

- 12,503

Any inertial coordinate system will do

- #4

- 15

- 0

I just want to know when we solve differential equation ,why choosing a different original point and axes won't make any difference.Curl and divergence rely on the x,y,z.So please ingore the relativity chapter in Jackson's book or griffiths,and take chapter3,or 4 as an example.In the first several chapter we never mention the reference frame but with a lot of using curl and divergence.So in the first several chapter,when we do partial differentiation,we are doing it relative to which"x,y,z"?It is not a problem about relativity.

- #5

Mentor

- 34,516

- 12,503

This is just straight math. You should work this out for yourself. Transform from some T, X, Y, Z coordinate system towhy choosing a different original point and axes won't make any difference.Curl and divergence rely on the x,y,z.

T=t+t0

X=x+x0

Etc.

Substitute into Maxwell’s equations and simplify. What do you get?

Share:

- Replies
- 8

- Views
- 704

- Replies
- 1

- Views
- 446

- Replies
- 2

- Views
- 548

- Replies
- 7

- Views
- 873

- Replies
- 9

- Views
- 642

- Replies
- 2

- Views
- 840

- Replies
- 4

- Views
- 490

- Replies
- 27

- Views
- 931

- Replies
- 1

- Views
- 468

- Replies
- 2

- Views
- 461