Maxwell's Equations & Wave Equation: An Overview

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may de vera
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Let respectively b = (b1, b2, b3) and e = (e1, e2, e3) denote the magnetic
and electric field in some medium. They are governed by Maxwell’s equations which look as follows:
(0.1) [tex]\partial[/tex]te = curl b
(0.2) [tex]\partial[/tex]tb = − curl e
(0.3) div e = 0
(0.4) div b = 0.
Show that each bi and each ei satisfies the wave equation
([tex]\partial[/tex]t2 - [tex]\Delta[/tex]) [tex]\varphi[/tex]=0
 
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taking curl of both side:
curl (dt e) = grad (div e) - laplacian (e)
curl (dt e) = grad (0) - laplacian (e)

i don't know what I'm doing =(
 
curl (dt e) = -laplacian (b)
dt (curl e) = -laplacian (b)
-dt b = -laplacian (b)
dt b = laplacian (b)
0 = laplacian (b)

and then taking curl of 0.2:
dtb = -curl e
curl (dt b) = curl (-curl e)
dt (curl b) = -curl (curl e)
dt (e) = -grad( div e) - laplacian (e)
= -grad (0) - laplacian (e)
dt (e) = - laplacian (e)
0 = laplacian e

how does that satisfy the wave equation? is it because that they both equal to zero?
 
You aren't being very careful with signs and you are dropping a dt. dt(dt(e))=[itex]\partial^2_t E[/itex]. Why are you turning dt(e) and dt(b) into zero? You want to get dt(dt(b))=laplacian(b) and the same for e.
 
i finally got down to: dt(dt(b)) = laplacian (b) and dt(dt(e))= -laplacian e

i still don't understand how that applies to the wave equation.
 
may de vera said:
i finally got down to: dt(dt(b)) = laplacian (b) and dt(dt(e))= -laplacian e

i still don't understand how that applies to the wave equation.

You've STILL got a sign wrong in the e part. What you've quoted in the problem as the wave equation is what we've been writing as dt(dt(phi))-laplacian(phi)=0. Look up those symbols.
 
i found out where i made a mistake with that negative sign. i got it now. thank you so so muchhhhh! happy thanksgiving!