Mean Value Theorem: Estimating f(0.1)

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SUMMARY

The discussion focuses on applying the Mean Value Theorem to estimate the value of the function f at x = 0.1, given that f'(x) = 1 / (1 + x^4 cos x) for the interval [0, 0.1] and f(0) = 1. The minimum and maximum values of f' on this interval are crucial for establishing bounds on f(0.1). By calculating f'(0) and using a calculator to approximate f'(0.1), participants derive inequalities that help estimate f(0.1) based on the Mean Value Theorem.

PREREQUISITES
  • Understanding of the Mean Value Theorem
  • Basic calculus concepts, including derivatives
  • Familiarity with trigonometric functions and their behavior
  • Calculator proficiency for evaluating functions
NEXT STEPS
  • Learn how to apply the Mean Value Theorem in different contexts
  • Explore the behavior of the function f'(x) = 1 / (1 + x^4 cos x)
  • Study numerical methods for estimating function values
  • Investigate the implications of derivative bounds on function behavior
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Students studying calculus, particularly those focusing on the Mean Value Theorem, as well as educators seeking to clarify concepts related to derivatives and function estimation.

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Homework Statement



Let f be a function defined on an interval [a,b]. min f' <= f(b) - f(a) / b -a <= max f' where min f' and max f' refer to the mininmum and maximum values of f' on [a,b]

Then the question is
Using that inequality; estimate f(.1) if f'(x) = 1 / (1 + x^4 cos x) for 0 <= x <= .1 and f(0) = 1


The Attempt at a Solution



I really don't know where to start with this, I have min f'(x) <= f'(c) <= max f'.
The book says to use a calculator too.
 
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For your interval, a = 0 and b = .1. You are given that f'(x) = 1/(1 + x^4 cos x). Clearly f'(0) = 1, and this will be the maximum value of f' on the interval in question. Use your calculator to get an approximate value for f'(.1).

In the following inequality, min f' and max f' refer to the minimum and maximum of f' on the interval [0, .1].
min f' <= (f(.1) - f(0))/.1 <= max f'
==> .1*(min f') <= f(.1) - f(0) <= .1*(max f')

Now add f(0), which is given, to all members of this inequality to get a lower bound and an upper bound on f(.1).
 
Hint: State the mean value theorem if a = 0 and b = .1 and use what you are given.
 

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