Meaning of the notations: ##\mathbb{Z}[\frac{1}{a}]##

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SUMMARY

The notation ##\mathbb{Z}[\frac{1}{a}]## represents the set of all polynomials in the variable ##\frac{1}{a}## with integer coefficients, derived from the polynomial ring ##\mathbb{Z}[x]##. Specifically, ##\mathbb{Z}[\frac{1}{6}]## is defined as the set of all such polynomials where ##x## is substituted with ##\frac{1}{6}##. Additionally, ##\mathbb{Z}[\frac{1}{2},\frac{1}{3}]## is similarly defined by substituting ##x## with ##\frac{1}{2}## and ##y## with ##\frac{1}{3}## in the polynomial ring ##\mathbb{Z}[x,y]##.

PREREQUISITES
  • Understanding of polynomial rings, specifically ##\mathbb{Z}[x]## and ##\mathbb{Z}[x,y]##.
  • Familiarity with the concept of isomorphism in abstract algebra.
  • Basic knowledge of the notation and operations involving rational numbers.
  • Knowledge of the properties of integers and their subsets.
NEXT STEPS
  • Study the properties of polynomial rings, focusing on ##\mathbb{Z}[x]## and its extensions.
  • Explore the concept of isomorphism in algebraic structures, particularly in relation to subsets of integers.
  • Learn about the implications of substituting variables in polynomial expressions.
  • Investigate the applications of ##\mathbb{Z}[\frac{1}{a}]## in number theory and algebra.
USEFUL FOR

Students and educators in abstract algebra, mathematicians interested in polynomial rings, and anyone seeking to deepen their understanding of algebraic structures and their notations.

elias001
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The following is taken from Abstract Algebra: A First Course by Stephen Lovett

Background

Exercise Let ##D=\{2^a 3^b\mid a,b,\mathbb{N}\}## as a subset of ##\mathbb{Z}##. Prove that ##D^{-1}\mathbb{Z}## is isomorphic to ##\mathbb{Z}[\frac{1}{6}]## even though ##D\neq\{1,6,6^2,\ldots\}##


Question:

I would like to know how is the notation: ##\mathbb{Z}[\frac{1}{6}]## or ##\mathbb{Z}[\frac{1}{a}]## defined? Also I have seen ##\mathbb{Z}[\frac{1}{2},\frac{1}{3}]##, and I would like to know how that is also defined.


Thank you in advance.




Thank you in advance
 
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\mathbb{Z}\left[\frac{1}{6}\right] are all polynomials in 1/6 with integer coefficients. It is what you get if you substitute x=1/6 in polynomials from \mathbb{Z}[x].

The same for \mathbb{Z}\left[\frac{1}{a}\, , \,\frac{1}{3}\right]. Take \mathbb{Z}[x,y] and replace x=1/a and y=1/3.
 

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