Measuring Torque of a Stepper Motor Using a Suspended Weight Method

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Homework Help Overview

The original poster attempts to measure the torque of a stepper motor using a suspended weight method, expressing uncertainty about the correct approach and calculations involved. The discussion revolves around the principles of torque, force, and distance in a rotational context.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between torque, force, and distance, questioning the original poster's proposed method and suggesting alternative approaches, such as using a pivot or a spring scale. There are inquiries about the importance of the moment arm and the radius of the shaft in the calculations.

Discussion Status

Multiple interpretations of the torque measurement method are being explored, with some participants providing guidance on the equations and concepts involved. The original poster expresses confusion about the correct application of these principles and the feasibility of their proposed method.

Contextual Notes

The original poster mentions constraints such as a lack of access to specific measuring tools like a spool or spring scale, relying instead on basic tools like a ruler and protractor for their measurements.

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1. The problem statement, all variables and given/known data

I am trying to experimentally measure the torque of a stepper motor at various velocities. I'm not quite sure how this should be done. Here is a diagram of my proposed method so far:

259uxro.jpg

Basically a weight is to be suspended from the motor by a string, and I will measure by how much the string has moved up after one full revolution. Then I believe the torque must be: ##\tau = m \times g \times \Delta L##. Is this a correct method?

Homework Equations



Torque = Force x Distance

The Attempt at a Solution



I would greatly appreciate it if someone could confirm whether this is a correct method to get a roughly correct measurement of torque (within perhaps ~80% of the manufacturer quotedvalue at a given velocity)?

Do I need to take the shaft diameter into account (or perhaps some other factors)? What is the simplest way of doing this? :confused:
 
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Torque = Force x Distance
... sort of: the "distance" in question cannot be any old distance - it has to be the length of the moment arm. In your equation ##mg\Delta L## is the work, ##W=Fd##, not the torque.

The equivalent relation for rotation is ##W=\tau\theta## ... where the angle is in radians.
 
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Another way to measure the torque is to mount the motor on a pivot so the case can rotate (within limits), attach an arm to it with some sort of spring scale on the end.
 
Also in your diagram the Moment Arm - is the radius of the shaft ( from the center to where the string contacts it- so pretty small) -- so you can decrease the needed weight but adding a wheel/spool to the shaft to increase the radius. By choosing a good radius it will make the calculations easier ( e.g. if you want In*Lbs as units- use a 1" radius wheel)
 
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Thank you Simon, CWatters, Windadct for your responses. I'm still a bit confused.

So, basically, I must measure the radius and use ##\tau= mg \times r##, OR find the angle and use ##\tau = (mg \Delta L)/\theta##?

When the motor turns the string will be wound around the stepper motor shaft, and I must measure the shaft radius with string around it (the amount of string is supposed to change by a minuscule amount whenever I change the speed). I think this would be a very difficult and inaccurate way of measuring ##\tau##...

In the diagram below I have indicated ##\theta##:

i1mpht.jpg


Is this the right idea? This angle can be measured with a protractor. Even if the string is wound several times and we get the same θ, ΔL would be different. Therefore we get different torques each time. So is this a correct method?

P.S. Unfortunately I do not have access to an appropriate spool, or a spring scale at the moment. I have to work with only a ruler and a protractor.
 
Neglecting energy that goes to turn the motor components: $$\tau_{ave} = \frac{mg\Delta L}{2N\pi}$$ would be a reasonable approximation.
Notice that's an average for N entire turns. Picking a big value for N will probably be best.

##\vec \tau = \vec F_g\times \vec r \implies \tau=mgr## ...where r is the radius of the shaft, would be the torque exerted by gravity.
Since the stepper motor accelerates around one turn, it must be providing more torque than that.
 
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Thank you for the explanation Simon. It's all clear now. :)
 

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