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Sandesh_10

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## Homework Statement

There is 14 kg of mass kept on a chassis (consider chassis weightless). Chassis is having 2 identical rear wheels and 2 Steel caster ball wheels at front. Consider the weight distribution to be equal on each of the wheel. All wheels are coupled to a DC motor-gearbox (1:1) each.The Rear Wheels are having 80mm diameter and made up of rubber and the chassis car is to be moved on a dry vinyl flooring. Adhesion coefficient,μ = 0.85.

Find the motor torque required if the car is to be moved at 1.2 m/s.

## Homework Equations

Torque, τ = F * D/2

F : traction force required

D: diameter of wheel

Traction force, F= β * W

W : weight

β : adhesion factor

## The Attempt at a Solution

F = 0.85 * 14*9.81 = 116.74 N

and thus

τ = 116.74 * 0.080/2 = 4.67 N.mm

Are these formulations and method correct?

Where and how does the velocity comes into picture?

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