Mechanical engergy, energy conservation

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SUMMARY

The discussion focuses on a physics problem involving mechanical energy conservation and the calculation of velocity for a block sliding down a frictionless track. The block, with a mass of 10 kg, reaches point B with a velocity of 8.85 m/s before encountering a frictional segment between points B and C, where it loses 88.2 J of energy. The key equation used is Wf = E2 - E1, which leads to determining the velocity after passing through points B and C by considering the energy loss and the combined mass of the blocks during the collision.

PREREQUISITES
  • Understanding of mechanical energy conservation principles
  • Familiarity with kinetic and potential energy equations (1/2mv^2, mgh)
  • Knowledge of work-energy theorem (Wf = E2 - E1)
  • Basic concepts of collisions and momentum conservation
NEXT STEPS
  • Calculate the velocity of the combined blocks after the collision using conservation of momentum
  • Explore the effects of friction on energy loss in mechanical systems
  • Study the behavior of springs in energy conservation problems (1/2kx^2)
  • Review advanced topics in energy transformations in mechanical systems
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and energy conservation, as well as educators seeking to enhance their understanding of practical applications of these concepts.

Gewitter_05
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Homework Statement


A 10-kg block is released from point A. The track is frictionless except from the portion between B and C which has a length of 3.0 meters. The block travels down the track, passes through BC and first collides with a small block (m=2kg), then they travel together and later hit the spring.

Q: Find the velocity of the block after it passes BC

There were two questions before it, find the velocity of the block when it reaches point B at the bottom of the track and it's 8.85m/s then I found the work between B and C which is -88.2 J. I tried setting up different equations to find the velocity after it passes B and C, but I am missing something.

Homework Equations


Wf=E2-E1
E2=E1
1/2mv^2, mgh, 1/2kx^2, mgx

The Attempt at a Solution


I tried setting the equation equal to the work, -88.2=1/2V^2(m+m), I recently tried -2μkgd=mv2^2-(mv1^2+2mgh1). I am not sure if I am supposed to have the second block in there or not.
 

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For the velocity at point C, the second block does not matter - it is not a part of the motion yet.
You probably have the energy of the first block at point B as intermediate result. If it loses 88.2J, what is its energy at point C? This allows to calculate the velocity.
 

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