Mechanics of an inertial balance

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SUMMARY

The discussion centers on the mechanics of an inertial balance, specifically how unequal masses lead to unequal accelerations and rotational motion of the rod. Participants explore the mathematical proof of this phenomenon using angular momentum, emphasizing that the system is in rotational equilibrium only when the sum of angular momenta is zero. The conversation highlights the importance of analyzing the center of mass (CoM) frame to understand inertial forces and net torque, while questioning the necessity of CoM concepts for simpler explanations. The role of Newton's Third Law in establishing equal forces on the masses is also examined.

PREREQUISITES
  • Understanding of angular momentum (L = r x p)
  • Familiarity with Newton's Third Law of Motion
  • Basic knowledge of rotational dynamics
  • Concept of center of mass (CoM) in mechanics
NEXT STEPS
  • Study the principles of angular momentum in detail
  • Learn about the center of mass and its applications in mechanics
  • Explore the implications of Newton's Third Law in rotational systems
  • Investigate net torque calculations in systems with unequal masses
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Physics students, educators, and anyone interested in understanding the dynamics of inertial balances and rotational motion in mechanics.

Quantum55151
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In the following diagram (from Taylor's Classical Mechanics), an inertial balance is shown.

1719947221301.png


Intuitively, I totally understand that unequal masses would cause unequal accelerations and therefore rotational motion of the rod. However, how does one prove this mathematically?

The first thing that came to mind was to look at the situation from the point of view of angular momentum. The system is in rotational equilibrium if and only if the sum of the angular momenta of the two masses is zero, where L = r x p. But since the masses are subject to unequal accelerations, at any instant in time after the force is applied, p1 is not equal to p2, and so the sum of L cannot possibly zero. However, this explanation seems quite hand-wavy to me, so I'm wondering if anyone could suggest a more rigorous treatment of the problem.
 
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Just look at the CoM frame of the system (ie, an accelerating frame accelerating with the CoM). This factors out the translational part of the motion and you are left with the inertial forces mg acting on each mass. If the masses are different there is a net torque about the mid point (meaning a net torque everywhere as the total force is zero in the CoM frame by definition).
 
Orodruin said:
Just look at the CoM frame of the system (ie, an accelerating frame accelerating with the CoM). This factors out the translational part of the motion and you are left with the inertial forces mg acting on each mass. If the masses are different there is a net torque about the mid point (meaning a net torque everywhere as the total force is zero in the CoM frame by definition).
Is there a simpler way of looking at it that does not involve CoM? I'm just not too familiar with the concept.

Edit: should I maybe just wait until CoM is formally introduced in the book before tackling the problem?
 
Last edited:
Quantum55151 said:
Is there a simpler way of looking at it that does not involve CoM?
The force on each object is the same, therefore they will have identical acceleration iff they have identical masses.
 
Mister T said:
The force on each object is the same, therefore they will have identical acceleration iff they have identical masses.
What is this assumption based on? Sure, there is a force applied at the center of the rod, but why are we allowed to say that the same force acts on both masses?
 
Quantum55151 said:
What is this assumption based on? Sure, there is a force applied at the center of the rod, but why are we allowed to say that the same force acts on both masses?
Third law says that the force on the rod from each mass is opposite and equal to the force on each mass from the rod. The rod is not rotating so the forces of the rod are equal; therefore the forces on the masses must also be equal.

Whether this is less hand-wavey than your original solution is an open question. It is certainly less elegant than @Orodruin ’s.
 
Quantum55151 said:
What is this assumption based on?
The fact that the rod doesn't rotate.
 

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