Mechanics of Materials - Deflection of an L shaped beam

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SUMMARY

The discussion focuses on calculating the deflection, maximum normal stress, and maximum shear stress of an L-shaped beam under load. Key equations used include δ=(PL/EA) for deflection, σ=-My/I for normal stress, and τxy= VQ/IT for shear stress. Participants emphasize the importance of accounting for the beam's rotation at the corner joint when determining deflection, suggesting a method to geometrically find the deflection at the free end. The conversation highlights the need for precise boundary conditions and the correct application of formulas to achieve accurate results.

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chris627
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Homework Statement


EDFVJdM.png

A. determine the deflection at point A in the X and Y direction.
B. determine the maximum normal stress in the beam
C. determine the maximum shear stress in the beam


Homework Equations


δ=(PL/EA)
(possibly?) δt=αΔτL
d2v/dx2 = M/EI
dM/dx = V
δabx*cosθ + δy*sinθ
σ=-My/I y- the distance from the neutral axis
τxy= VQ/IT

The Attempt at a Solution


I tried to split this problem into separate deflections.

First, the deflection due to the normal force:
δy= -(Pb)/(Ewd)

Next, the deflection due to the moment on the bar with width W:
Vx= (12Pab2)/(Edw3)

Finally, I related the deflection on the section with width t to the deflection on the bar with a width W:
My boundary conditions are as follows
dv/dx = -1/(dv/dxw) since they are perpendicular
V(0) = δy

Using these boundary conditions I found that when X=a... this is going to get messy.
Vy= 12/Edt3 [(-pa3/3)+(E2d2w2t2/144pb)-(pbt3/12w)]

My intuition tells me this is incorrect since there is an E2 term in there. I obtained the E2 term when I related the slopes of the t and w bars.

For V in the x direction...
Vx= (12pab2/2Edw2)


For parts B and C, I simply plugged in P for Vmax, and P*a for Mmax into the equations:
τxy= VQ/IT
σ=-My/I

Homework Equations


Are these the correct equations for deflection in the x and y? Do I need to account for the rotation of the beam, or is that already accounted for in these equations?

Thanks. Any help would be greatly appreciated.
 
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chris627 said:

Homework Statement


EDFVJdM.png

A. determine the deflection at point A in the X and Y direction.
B. determine the maximum normal stress in the beam
C. determine the maximum shear stress in the beam


Homework Equations


δ=(PL/EA)
(possibly?) δt=αΔτL
d2v/dx2 = M/EI
dM/dx = V
δabx*cosθ + δy*sinθ
σ=-My/I y- the distance from the neutral axis
τxy= VQ/IT

The Attempt at a Solution


I tried to split this problem into separate deflections.

First, the deflection due to the normal force:
δy= -(Pb)/(Ewd)
Looks good
Next, the deflection due to the moment on the bar with width W:
Vx= (12Pab2)/(Edw3)
should be 6 not 12
Finally, I related the deflection on the section with width t to the deflection on the bar with a width W:
My boundary conditions are as follows
dv/dx = -1/(dv/dxw) since they are perpendicular
V(0) = δy

Using these boundary conditions I found that when X=a... this is going to get messy.
Vy= 12/Edt3 [(-pa3/3)+(E2d2w2t2/144pb)-(pbt3/12w)]

My intuition tells me this is incorrect since there is an E2 term in there. I obtained the E2 term when I related the slopes of the t and w bars.
seems like you should calculate the deflection as a simple cantilever, then add the deflection caused by the rotation at the corner joint
For V in the x direction...
Vx= (12pab2/2Edw2)
What's this?
For parts B and C, I simply plugged in P for Vmax, and P*a for Mmax into the equations:
τxy= VQ/IT
where I = ?
σ=-My/I
this would be bending normal stress where? What about axial stress? I don't know how you can determine the max without knowing values for the givens

Homework Equations


Are these the correct equations for deflection in the x and y? Do I need to account for the rotation of the beam, or is that already accounted for in these equations?

Thanks. Any help would be greatly appreciated.
in calculating the deflection at the free end, you account for the deflection caused by rotation by calculating the rotation of the vertical piece at the corner joint, then geometrically find the deflection at the free end of the top piece which goes along for the ride so to speak.
 

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