Mechanics of Materials - Shear and Compression

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Homework Help Overview

The discussion revolves around a mechanics of materials problem involving shear and compression forces on an axis with given parameters such as load, diameter, thickness, and safety coefficient. Participants are tasked with checking the axis for strength based on shear and compression criteria.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the meanings of various symbols and formulas related to shear and tensile strength. There are questions about the application of specific factors in calculations and the interpretation of different material strengths. Some participants express uncertainty about the technical aspects and seek clarification on terms and relationships between strengths.

Discussion Status

The discussion is ongoing, with participants sharing their interpretations and questioning the correctness of certain calculations and symbols. There is no explicit consensus, but several participants are actively engaging in clarifying terms and exploring the relationships between different material properties.

Contextual Notes

Some participants indicate a lack of familiarity with certain technical aspects, which may affect their understanding of the problem. There are references to specific formulas and factors that are not fully explained, leading to further inquiry and discussion.

Femme_physics
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I do not know what all your symbols mean, but your calculation for the shear stress and tensile strength is correct.

I do see that your relevant formula mentions 0.5/0.6, while you apply 1.5/2.0.
Is that intentional?
TBH, I do not know what this factor is. Do you?
 
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Sorry it took me a while to reply, I had a materials strength lab reports to give.

I do see that your relevant formula mentions 0.5/0.6, while you apply 1.5/2.0.
Is that intentional?
TBH, I do not know what this factor is. Do you?

I was hoping you'd tell me that :smile:

Well, so my answer is correct? At any rate, let's interpret the symbols. Ts [N/mm^2] = max shearing strength in the part
Fmax [N] – Max shearing force
As = Area of shearing
[T] = allowable shearing strength
Safe factory

Sigma/c [N/mm^2] – Max compression strength in the part
Fmax = max compression force
A/c = area of the compression
[Sigma/c] [Mpa] – allowable compression strength
safely coeffecient
 
How did the material strengths lab report go?


Well, I didn't study material sciences, so there are a few technical aspects that escape me...

What is [itex]d \cdot t_{min}[/itex]?
And your formulas appear to contain [itex]lc[/itex] instead of [itex]/c[/itex]...?
What are [itex][\sigma_t][/itex] and [itex]\sigma_y[/itex]?
What's the difference between shearing strength and compression strength?

I would expect the extra factor to be some type of rule-of-thumb factor, but I have no clue for what...
 
How did the material strengths lab report go?

Great! I copied it from the smartest guy in class (specifically said "guy" :wink: ) so it have better turned out great. I just don't like to give out reports as much as I like to solve exercises.

I don't see d x t (min)

As far as Ic instead of /c, I might have miscopied! Not sure whether it's "I" or "/"

Sigma y is "yield strength"
Sigma t is (I think) "tensile strength". There's appearing a relation between that and compression or shearing strength.
What's the difference between shearing strength and compression strength?

pushpull.gif


:smile:
 
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Femme_physics said:
Great! I copied it from the smartest guy in class (specifically said "guy" :wink: ) so it have better turned out great. I just don't like to give out reports as much as I like to solve exercises.

I'm certain it would turn out even better if you let the smartest person in class do it! :smile:


Femme_physics said:
I don't see d x t (min)

There it is!
http://img202.imageshack.us/img202/8345/formulas2.jpg


Femme_physics said:
As far as Ic instead of /c, I might have miscopied! Not sure whether it's "I" or "/"

Sigma y is "yield strength"
Sigma t is (I think) "tensile strength". There's appearing a relation between that and compression or shearing strength.

Okay... I'll just accept that for now...


Femme_physics said:
http://jclahr.com/science/earth_science/tabletop/pushpull.gif

:smile:

Aha!
 
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