Mechanics of materials - shear flow in built up members

AI Thread Summary
The discussion focuses on understanding shear flow in built-up members, specifically how to apply the shear formula tau = VQ/It. The confusion arises regarding the use of the cross-sectional area A', where it is clarified that only one of the top boards is considered because the shear flow is evenly distributed across symmetrical sections. This approach simplifies the analysis, as both top and bottom boards have similar areas and experience the same shear force. The goal is to determine the minimum resistance to shear force for each section of a bolt under load. The explanation emphasizes treating each segment separately while recognizing the uniform distribution of shear in symmetrical beams.
nate_cal
Messages
1
Reaction score
0
TL;DR Summary
I do not really understand how to determine the value Q from the shear formula for this example.
Hello!

I am new to mechanics of materials and I am very confused about the problem below. So the shear formula is:

tau = VQ/It

From the book (Hibbeler) I understand that Q is "y'A', where A' is the cross-sectional area of the segment that is connected to the beam at the juncture where the shear flow is calculated, and y' is the distance from the neutral axis to the centroid of A'". However, for this case I do not understand why A' is only one of the top boards (red area) and not both, if the bolt goes through all the 3 boards.

question.PNG
 
Engineering news on Phys.org
This example is from the chapter about built-up members - beams consisting of several connected parts. Each segment is treated separately in these calculations and thus the cross-sectional area of a single segment is used.
 
Welcome! :cool:

Could you show us the solution or explanation provided by the book?
It seems the goal is to determine the minimum resistance to shear force of each of the sections of one bolt under that type of load.

Why A' is only one of the top boards?
Since the beam is symmetrical and both cross-sections of one bolt have similar area, analyzing one is sufficient, as the shear flow is evenly distributed for both cross-sections, as well as for both, top and single bottom wood boards.

Yours is case b) in the picture below.

Please, see:
http://www.engineeringcorecourses.com/solidmechanics2/C3-transverse-shear/C3.1-shear-flow/question2/

https://mathalino.com/reviewer/mechanics-and-strength-of-materials/shear-stress

Shear flow.jpg


 
Last edited:
Thread 'What type of toilet do I have?'
I was enrolled in an online plumbing course at Stratford University. My plumbing textbook lists four types of residential toilets: 1# upflush toilets 2# pressure assisted toilets 3# gravity-fed, rim jet toilets and 4# gravity-fed, siphon-jet toilets. I know my toilet is not an upflush toilet because my toilet is not below the sewage line, and my toilet does not have a grinder and a pump next to it to propel waste upwards. I am about 99% sure that my toilet is not a pressure assisted...
After over 25 years of engineering, designing and analyzing bolted joints, I just learned this little fact. According to ASME B1.2, Gages and Gaging for Unified Inch Screw Threads: "The no-go gage should not pass over more than three complete turns when inserted into the internal thread of the product. " 3 turns seems like way to much. I have some really critical nuts that are of standard geometry (5/8"-11 UNC 3B) and have about 4.5 threads when you account for the chamfers on either...
Thread 'Physics of Stretch: What pressure does a band apply on a cylinder?'
Scenario 1 (figure 1) A continuous loop of elastic material is stretched around two metal bars. The top bar is attached to a load cell that reads force. The lower bar can be moved downwards to stretch the elastic material. The lower bar is moved downwards until the two bars are 1190mm apart, stretching the elastic material. The bars are 5mm thick, so the total internal loop length is 1200mm (1190mm + 5mm + 5mm). At this level of stretch, the load cell reads 45N tensile force. Key numbers...
Back
Top