Undergrad Mechanics problem: A Weight and a Mass Suspended from a String

Click For Summary
SUMMARY

The discussion centers on the mechanics of static equilibrium involving a weight and a mass suspended from a string. Participants emphasize the necessity of showing work to receive assistance. Key equations derived include Tsin(φ) = Fcos(α) for the x-component and Fsin(α) + G = Tcos(φ) for the y-component. A critical point of confusion arises regarding the appearance of α/2 in the solution, prompting further exploration of torque equations and the geometry involved in the problem.

PREREQUISITES
  • Understanding of static equilibrium principles
  • Familiarity with force decomposition into components
  • Knowledge of torque equations in mechanics
  • Basic geometry related to angles and forces
NEXT STEPS
  • Study the application of torque equations in rigid body mechanics
  • Learn about the principles of static equilibrium in physics
  • Explore the concept of force decomposition in two dimensions
  • Investigate the role of angles in tension and force applications
USEFUL FOR

Students and professionals in physics, particularly those focusing on mechanics, as well as educators seeking to clarify concepts of static equilibrium and force analysis.

smnjech
Messages
3
Reaction score
0
TL;DR
I have difficulty solving this problem.

A homogeneous sphere of weight G, radius R is suspended at location 0 together with a weight of weight P in the manner indicated in Fig. 2.5. Determine the angles and the force F acting on the sphere from the hinge of the weight P.

The thing that makes me confused is that in the solution of the problem stated in the book, the angle of α/2 appears and I do not know why.
20230821_182648.jpg
 
Physics news on Phys.org
You need to show your work. We can't give help until you show an effort.
 
phinds said:
You need to show your work. We can't give help until you show an effort.
The main idea that I started with was that there has to be static equilibrium, so the sum of all forces acting on a sphere must give zero. I decomposed the forces into x and y components and for the x component I came up with Tsin(φ)=Fcos(α) and for y component Fsin(α)+G=Tcos(φ). But when I later looked at the solution there was α/2 instead of α and I dont umderstand why.
 
You need the torque equation with respect to the point O to the whole system and a lot of geometry.
 
Last edited:
smnjech said:
The main idea that I started with was that there has to be static equilibrium, so the sum of all forces acting on a sphere must give zero. I decomposed the forces into x and y components and for the x component I came up with Tsin(φ)=Fcos(α) and for y component Fsin(α)+G=Tcos(φ). But when I later looked at the solution there was α/2 instead of α and I dont umderstand why.
I am trying to decode your equations to figure out why you think they apply.

So ##F## is the tension in the right hand cord supporting weight ##P##. You seem to think that this force is applied at an angle ##\alpha## below the horizontal to the sphere.

Can you identify the two angles where the cord meets the sphere above its equator and then departs from the sphere at its equator? What is the average of those two angles?

At what angle, on average, does the contact force of cord on sphere act?
With what net force does it act?
 
smnjech said:
The thing that makes me confused is that in the solution of the problem stated in the book, the angle of α/2 appears and I do not know why.
Show us the expression in which ##\alpha /2## appears.
 
Is ##\ell## a rod that connected to the sphere perpendicular and such that they both form a rigid body?
 
wrobel said:
Is ##\ell## a rod that connected to the sphere perpendicular and such that they both form a rigid body?
Yes it is.
 
Then it is indeed a simple application of the torque equation.
 
  • #10
Welcome, @smnjech !

Could you identify the terms T and F in the shown equations?

Consider that the string is always wrapping the sphere, for any position.
The force that the string applies on the sphere is always pointing to its center (perpendicular direction to the tangent line formed by both sides of the string).

What is the angle that each of those sides symmetrically form with that tangent line?

Nd9GcTr9fHMJ0g-TmOkKNnbiEHBHTrQnobvcJMd4Q&usqp=CAU.png
 
Last edited:
  • #11
Lnewqban said:
The force that the string applies on the sphere is always pointing to its center
not always but in the absence of friction
 

Similar threads

  • · Replies 20 ·
Replies
20
Views
814
  • · Replies 19 ·
Replies
19
Views
2K
  • · Replies 24 ·
Replies
24
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 29 ·
Replies
29
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 6 ·
Replies
6
Views
5K