- #1
~Death~
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I need to compute integral x^(1/4)/(x^2+9)dx from 0 to infinity
so I use a formula
-pie^(-5pi/4i)/sin(5pi4)SUM residues z^(5/4-1)/(z^2+9) so that's sqrt2pie^(-5pi/4i)3^(1/4)/(6i)(e^(pi/8i)-e^(3pi/8i)) (with the 0<arg<2pi branch of sqrt) but e^(-7pi/4)(e^(pi/8i))-e^(3pi/8i)) which is some horrible number...and that's not the answer according to my book
=(
so I use a formula
-pie^(-5pi/4i)/sin(5pi4)SUM residues z^(5/4-1)/(z^2+9) so that's sqrt2pie^(-5pi/4i)3^(1/4)/(6i)(e^(pi/8i)-e^(3pi/8i)) (with the 0<arg<2pi branch of sqrt) but e^(-7pi/4)(e^(pi/8i))-e^(3pi/8i)) which is some horrible number...and that's not the answer according to my book
=(