- #1

- 45

- 0

## Main Question or Discussion Point

I need to compute integral x^(1/4)/(x^2+9)dx from 0 to infinity

so I use a formula

-pie^(-5pi/4i)/sin(5pi4)SUM residues z^(5/4-1)/(z^2+9) so thats sqrt2pie^(-5pi/4i)3^(1/4)/(6i)(e^(pi/8i)-e^(3pi/8i)) (with the 0<arg<2pi branch of sqrt) but e^(-7pi/4)(e^(pi/8i))-e^(3pi/8i)) which is some horrible number...and thats not the answer according to my book

=(

so I use a formula

-pie^(-5pi/4i)/sin(5pi4)SUM residues z^(5/4-1)/(z^2+9) so thats sqrt2pie^(-5pi/4i)3^(1/4)/(6i)(e^(pi/8i)-e^(3pi/8i)) (with the 0<arg<2pi branch of sqrt) but e^(-7pi/4)(e^(pi/8i))-e^(3pi/8i)) which is some horrible number...and thats not the answer according to my book

=(