Melting Ice in Seawater: Cooling Steel on Seabed with 30kg Ice Block at -20degC

AI Thread Summary
To cool a 1kg steel piece on the seabed using a 30kg ice block at -20°C, the melting ice will absorb heat from the steel, which is initially at 12°C. The final temperature of the steel before the ice completely melts depends on the rates of heat transfer between the ice, steel, and surrounding seawater. A temperature gradient will form around the ice during the melting process, creating a non-equilibrium situation. If the steel is assumed to be a good conductor and not influenced by the seabed or seawater, the final temperature will be determined by the specific heat transfer rates involved. Ultimately, without reaching thermal equilibrium, the steel's temperature will not stabilize at 12°C until the ice has fully melted.
patfee
Messages
2
Reaction score
0
Using a 30kg cubic block Ice at -20degC, I want to cool down a piece of steel which is resting on the seabed. The mass of steel is 1kg and the ice block is place on top of the steel.
The current sea temperature as well as the steel temp is estimated at 12degC

Assuming that the piece of steel is not "heated" by the seabed, nor the sea water, the ice melts while cooling the steel.

Question is till what temperature can the steel be cooled before the ice is completely melted and dissolved.

I'm kinda lost here on the thermodynamics, since the "energy out" does not equal the "energy in" as the unlimited amount of seawater volume will melt the ice without increasing in temperature.

can someone push me in the right direction please.

thanks
Patrick
 
Physics news on Phys.org
I am afraid you cannot find the answer from pure energy balance.
The answer will depend on the rates of heat transfer from the water to the ice and steel to the ice.
There will be a temperature gradient building up around the ice block.
During melting you have a non-equilibrium situation. Water, ice and steel have different temperatures. I understand that you want to know what will be the temperature of the steel (assuming it is uniform, which may be a good approximation for a good conductor) at the very moment when the ice is completely melted.
So the answer will depend on the specific rates of heat transfer.

Unless you want to wait until equilibrium is reached again and then everything will be pretty much 12 degrees.
 
I am looking for the 'nub' of this question. Is the fact that the ice and steel are on the sea bed relevant to the question? (You say the steel is not heated by the sea bed or the sea water).
 
The rope is tied into the person (the load of 200 pounds) and the rope goes up from the person to a fixed pulley and back down to his hands. He hauls the rope to suspend himself in the air. What is the mechanical advantage of the system? The person will indeed only have to lift half of his body weight (roughly 100 pounds) because he now lessened the load by that same amount. This APPEARS to be a 2:1 because he can hold himself with half the force, but my question is: is that mechanical...
Some physics textbook writer told me that Newton's first law applies only on bodies that feel no interactions at all. He said that if a body is on rest or moves in constant velocity, there is no external force acting on it. But I have heard another form of the law that says the net force acting on a body must be zero. This means there is interactions involved after all. So which one is correct?
Thread 'Beam on an inclined plane'
Hello! I have a question regarding a beam on an inclined plane. I was considering a beam resting on two supports attached to an inclined plane. I was almost sure that the lower support must be more loaded. My imagination about this problem is shown in the picture below. Here is how I wrote the condition of equilibrium forces: $$ \begin{cases} F_{g\parallel}=F_{t1}+F_{t2}, \\ F_{g\perp}=F_{r1}+F_{r2} \end{cases}. $$ On the other hand...

Similar threads

Back
Top