Mesh Current Analysis for a Series-Parallel Circuit

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SUMMARY

The discussion focuses on mesh current analysis for a series-parallel circuit, specifically using Kirchhoff's Voltage Law (KVL) and Cramer's Rule. The participant initially calculated mesh currents I1, I2, and I3 but found discrepancies with instructor-provided answers of 8A and 10A for the 110V and 12V sources, respectively. Key errors identified include incorrect setup of equations for mesh currents, particularly the voltage drops across resistors. The correct formulation involves recognizing the direction of current flow and applying KVL accurately across the meshes.

PREREQUISITES
  • Understanding of Kirchhoff's Voltage Law (KVL)
  • Familiarity with Cramer's Rule for solving systems of equations
  • Knowledge of series-parallel circuit configurations
  • Basic principles of voltage drop across resistors
NEXT STEPS
  • Study advanced mesh current analysis techniques
  • Learn how to apply Cramer's Rule in electrical circuit analysis
  • Explore examples of KVL applications in complex circuits
  • Review common mistakes in setting up mesh equations
USEFUL FOR

Electrical engineering students, circuit designers, and anyone involved in analyzing series-parallel circuits using mesh current analysis.

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Homework Statement


problem3.jpg



Homework Equations


Not necessarily any equations ,just systematic approaches for mesh current analysis like using KVL
Also used cramer's rule


The Attempt at a Solution


My work:
http://i28.photobucket.com/albums/c216/aldodesigns/page1.jpg
http://s28.photobucket.com/albums/c216/aldodesigns/?action=view&current=page2.jpg

I found I1, I2, and I3 (I think) but they're not right. The answers my instructor gave us were 8A for the 110V source and 10A for the 12V source and I am way off. Did I set up my equations wrong?
 
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Take care of your signs. Across a resistor, the current direction is always from the more positive terminal to the more negative one. If you decided the direction of current than you have the voltage drop always in that direction. You do not have the freedom to choose which terminal of a resistor is more positive than the other one, and you do not know it before you solve the problem for the currents.

So your first equations for mesh 1 and 3 are wrong.

In case of mesh 1 you have the current I1 - I2 flowing through the 12 ohm resistor. Going clockwise, the voltage drop is 12(I1-I2). In mesh 3, I3 current flows through the 4 ohm resistor, causing 4 (I3) voltage drop.

ehild
 

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