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Mesh Current Analysis: Solve & Determine Magnitudes/Voltages
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[QUOTE="gneill, post: 5233054, member: 293536"] Given the above I don't see how you arrived at your two loop equations. If i3 has a given value, why does the i3 variable appear in the Loop1 equation? Loop 2 has a total of 16 Ohms in it, yet I don't see where your equation accounts for i2 flowing through that, nor how i1 is flowing through 4 Ohms for that loop when I see that a 5 Ohm resistor borders the loops. I think you need to redo your loop equations. In general it's usually beneficial to choose the same loop direction for all loops (one reason has to do with some really handy and time saving matrix solving methods that you'll learn about soon) Here's a diagram to help: [ATTACH=full]88918[/ATTACH] I suggest that as a first step you might eliminate the 3 A mesh by moving its effect into the i1 loop as a fixed voltage source (due to its flowing through the 16 Ohm resistor). [/QUOTE]
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Mesh Current Analysis: Solve & Determine Magnitudes/Voltages
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