MESH Current, Voltage Polarities

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SUMMARY

This discussion focuses on MESH Analysis, specifically the determination of voltage polarities across resistors in circuit loops. The user seeks clarification on how to assign voltage polarities when using clockwise loop currents. The provided equations for the left and right loops illustrate the application of Kirchhoff's Voltage Law, with the left loop equation being -9V + I1(5k) + (I1-I2)(6k) = 0 and the right loop equation being -9V - (I1-I2)(6K) + I2(12K) = 0. The key takeaway is that the polarities of resistors are dictated by the assumed direction of current flow.

PREREQUISITES
  • Understanding of MESH Analysis in electrical circuits
  • Familiarity with Kirchhoff's Voltage Law (KVL)
  • Basic knowledge of resistors and their behavior in DC circuits
  • Ability to interpret circuit diagrams and equations
NEXT STEPS
  • Study the principles of Kirchhoff's Voltage Law (KVL) in depth
  • Learn how to derive MESH equations for complex circuits
  • Practice with various examples of MESH Analysis using different current directions
  • Explore the impact of resistor values on voltage polarity in circuit analysis
USEFUL FOR

Electrical engineering students, circuit designers, and anyone looking to enhance their understanding of MESH Analysis and voltage polarity in DC circuits.

tylercormier2
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Hello,

I'm trying to figure out MESH Analysis but for the life of me I can't seem to get the Voltage polarities on the resistors right. I usually like to assign my loop currents clockwise so I can get in some sort of a routine(I know it makes no difference). Can someone please help me explain the voltage polarities across resistors?

Here is a DC example,
http://www.art-sci.udel.edu/ghw/phys245/05S/examples/images/Mesh-ex1.gif

Can someone please explain to me a method for choosing voltage polarities in these loops and give the MESH equations? I think I am just missing something basic, so a detailed explanation would be nice.
Thanks
 
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tylercormier2 said:
Hello,

I'm trying to figure out MESH Analysis but for the life of me I can't seem to get the Voltage polarities on the resistors right. I usually like to assign my loop currents clockwise so I can get in some sort of a routine(I know it makes no difference). Can someone please help me explain the voltage polarities across resistors?

Here is a DC example,
http://www.art-sci.udel.edu/ghw/phys245/05S/examples/images/Mesh-ex1.gif

Can someone please explain to me a method for choosing voltage polarities in these loops and give the MESH equations? I think I am just missing something basic, so a detailed explanation would be nice.
Thanks

Please show us what you think they are first, and then we can comment. Them's the PF Rules.

Welcome to the PF!
 
Alright,

Here`s how I would approach this problem,
Left Loop : -9v + I1(5k) +(I1-I2)(6k)=0 (Clockwise Current Direction)
Right Loop: -9v - (I1-I2)(6K) + I2(12K) = 0 (Clockwise Current Direction)

I`m not sure if this is right or not, it`s what I came up with. I think my problem is I am not 100% confident in my methods which would lead me to mistakes on tougher questions. Anyways, I`d appreciate your input.
Thanks again.
 
The thing I'm getting stuck on is always hearing "The polarities within each loop for each resistor are determined by the assumed direction of current."
Can someone explain this concept for me please?
 
The part where current flows into to a resistor is more positive than where it leaves.

In mesh analysis, assume that current flows in a loop in some direction.
 
Ahhhhh. Thank you. Thank you soooo much. I knew it was something basic I was missing.
 

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