Method to carry out the isobaric process

In summary, the conversation discusses processes in thermodynamics, particularly the isobaric process. The basic idea of pressure is explained, stating that it increases when volume is reduced while keeping temperature constant, or when temperature is raised while keeping the number of moles constant. A method to carry out the isobaric process is described, involving supplying heat to the system, allowing for an increase in temperature, and then increasing the volume while maintaining the initial temperature. The concept of an ideal gas and its behavior in an isobaric process is also mentioned. The conversation ends with a request for help understanding adiabatic compression and joule expansion of gases.
  • #1
A Dhingra
211
1
hi ...

These days i am trying to make sense of the various processes of thermodynamics and so far i have tried the isothermal process , and isochoric process (which is quite simple i think). Now i am trying to describe what i have understood by the isobaric process:

According to the basic idea of pressure: it increases when the volume is reduced keeping temperature nearly constant, and also when the temperature is raised keeping the no of moles constant. With this idea in mind i thought of a way to carry out the process.

If dQ amount of heat is supplied to the system in consideration, then its temperature increases by dT amount. Then the supply of heat is put off and the volume is allowed to increase by dV amount, and meanwhile the temperature is not allowed to fall below its initial value, in fact the source of heat is turned on as soon
dV = nR dT/P. And again the same cycle is repeated so the pressure remains constant.

So is it a method to carry out the process?
Do you think it is making sense and taking the form of a quasi-static isobaric process?
Or can you suggest a better method to carry out the isobaric process ?

I am looking forward to your quick reply...
 
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  • #2
I think you've got it right. For an ideal gas, as long as any change in temperature dT is accompanied by a change in volume dV = Nk/P dT, then pressure will remain constant. (Forgive me, but I really dislike the constant R, since R = k*A, where k is Boltzmann's constant and A is Avogadro's number, which is too chemistry-y for me.)

One way I like to understand this process is by thinking of a bubble of gas surrounded by another gas at pressure P, or, alternatively, a gas inside a cylinder equipped with a piston exerting a constant force F on the gas. When the gas inside the bubble is heated causing a temperature change dT, the pressure inside the bubble must equilibrate with the pressure outside, so a change dV must occur. Likewise, when the gas inside the piston undergoes a temperature change dT, the volume must change so that the force exerted on the piston by the gas equilibrates with the force F on the piston.

Maybe you could help me out with my as-yet unanswered question on adiabatic compression and joule expansion of gasses, which is a little further down in this board.
 
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  • #3
Jolb said:
One way I like to understand this process is by thinking of a bubble of gas surrounded by another gas at pressure P, or, alternatively, a gas inside a cylinder equipped with a piston exerting a constant force F on the gas. When the gas inside the bubble is heated causing a temperature change dT, the pressure inside the bubble must equilibrate with the pressure outside, so a change dV must occur. Likewise, when the gas inside the piston undergoes a temperature change dT, the volume must change so that the force exerted on the piston by the gas equilibrates with the force F on the piston.

I tried thinking this way of keeping pressure constant, but the number of molecules inside and outside the closed container will not be same ,then how will the pressure inside the container be balanced by smaller number of particles moving around with greater energy(so are at a higher temperature).
But if i try to see this from the point of view of Newton's third law, then the force between two particles is always equal and opposite on the two of them ... hence taking the system and surrounding as two huge particles...it seems they will never allow the pressure to differ, ensuring all the processes will be isobaric..
But i am really confused about all this..
 
  • #4
Perhaps this will help you both.

It is a good idea to understand the basics of thermo before learning the posh words like isobaric.

So what are the basics?

Well we need a system, we need the surroundings, we need the boundary between them and we need a process.

A system is a part of the universe considered separate from the rest of the universe by a well defined boundary.

The surroundings are the rest of the universe.

The process describes the exchange of energy (heat, work or some other form) across the boundary between the system and the rest of the universe.

That is the first law.

It is vital to realize that the work or heat is transferred across the boundary and does not occur exclusively within the system or surroundings.

This is important because we can calculate the heat transferred or the work done for either the surroundings or the system.

Of course
the heat transferred to the system = heat lost by the surroundings
the work done by the system = the work done on the surroundings.

So to isobaric processes.

Because we can perform our calculation for either the system or the surroundings and get the same answer we calculate for the most convenient.

We don't care what the pressure conditions within the system are or even if they are defined if we can say that the surroundings are at constant pressure. This is usually the case for chemical reactions or work done against the atmospheric pressure.

So we can say that the heat transferred at constant pressure = Cp ΔTsystem when we heat a beaker of water in the atmosphere.

If we heat a sealed container of gas ( balloon) in the atmosphere it expands against the pressure of the atmosphere ie the work done on the atmosphere (the surroundings) is done at constant pressure.
Since the volume lost by the surroundings = the volume gain by the balloon we can say that the work done by the balloon on the surroundings = Patmosphere ΔV

does this help?
 
  • #5


Hello, it sounds like you are on the right track in understanding the isobaric process. To carry out this process, you would need to have a system with a constant pressure and a source of heat. One method to achieve this would be to use a piston-cylinder system, where the piston can move to adjust the volume while the pressure remains constant. You would then supply heat to the system, causing the temperature to increase, and then allow the piston to expand to increase the volume while maintaining the same pressure. This process can be repeated to continue the isobaric process.

Another method could be using a constant pressure bath, where the system is placed in a bath of constant pressure and heated to increase the temperature. The volume can then be adjusted to maintain the pressure while the temperature remains constant. This process can also be repeated to continue the isobaric process.

Overall, your method of supplying heat and then allowing the volume to increase while maintaining the temperature and pressure is a valid way to carry out the isobaric process. However, using a piston-cylinder system or a constant pressure bath can provide a more controlled and accurate way to achieve this process. I hope this helps and good luck with your studies!
 

What is the isobaric process?

The isobaric process is a thermodynamic process in which the pressure of a system remains constant while other parameters, such as volume and temperature, may change.

What is the purpose of carrying out the isobaric process?

The purpose of carrying out the isobaric process is to study the behavior of a system under constant pressure. This can help in understanding the properties and characteristics of the system, and can also be used in various industrial processes.

How is the isobaric process carried out?

The isobaric process can be carried out by either increasing or decreasing the volume of the system while keeping the pressure constant. This can be achieved through various methods such as using a piston, changing the size of a container, or adjusting the flow rate of gases.

What are the applications of the isobaric process?

The isobaric process has various applications in industries such as chemical processing, refrigeration, and power generation. It is also used in laboratory experiments to study the behavior of gases and other substances under constant pressure.

What is the difference between isobaric and isothermal processes?

The main difference between isobaric and isothermal processes is that isobaric processes involve a constant pressure while isothermal processes involve a constant temperature. In isothermal processes, the pressure may vary as the volume changes. Additionally, the heat transfer in isobaric processes is not necessarily equal to zero, whereas it is zero in isothermal processes.

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