Metric space Triangular inequalities

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SUMMARY

The discussion focuses on proving the triangular inequality in a metric space (X, σ) for points x, y, and z in R. The key conclusion is that the absolute difference between the distances σ(x, z) and σ(y, z) is less than or equal to the distance σ(x, y). This is established using the properties of absolute values and the triangle inequality, demonstrating that |σ(x, z) - σ(y, z)| ≤ σ(x, y) holds true.

PREREQUISITES
  • Understanding of metric spaces and their properties
  • Familiarity with the triangle inequality in mathematics
  • Knowledge of absolute value properties
  • Basic skills in mathematical proofs and inequalities
NEXT STEPS
  • Study the properties of metric spaces in detail
  • Explore advanced applications of the triangle inequality
  • Learn about different types of metrics and their implications
  • Investigate examples of metric spaces beyond real numbers
USEFUL FOR

Mathematics students, particularly those studying analysis or topology, as well as educators looking to reinforce concepts related to metric spaces and inequalities.

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Homework Statement



let [tex] (X,\sigma)[/tex] be a metric space. [tex]xyz \in R[/tex]show that
[tex] \mid \sigma(x,z)-\sigma(y,z) \mid \leq \sigma(x,y)[/tex]

Homework Equations





The Attempt at a Solution



[tex]\mid \sigma(x,z)-\sigma(y,z) \mid \leq \sigma(x,y)=\mid \sigma(x,y) \mid = \mid\sigma<br /> (z,x) + \sigma(z,y) \mid[/tex]

[tex]\leq \mid\sigma<br /> (x,z)\mid + \mid \sigma(y,z) \mid[/tex]


Does that look alright?
 
Physics news on Phys.org
For real numbers a and b, |a+b| [tex] <br /> \leq [/tex] |a| + |b|.
Thus, |a| + |b|.= |(a-c) + (c-b)| [tex] <br /> \leq [/tex] |a-c| + |c-b|
 

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