Microscopic theory of superconductivity

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SUMMARY

The microscopic theory of superconductivity centers around the formation of Cooper pairs, which are quasiparticles that exhibit bosonic behavior, allowing them to occupy the same quantum state without restriction from the Pauli exclusion principle. This results in zero electrical resistance, as opposed to the resistance encountered by free electrons, which are fermions and require excitation to conduct. The discussion emphasizes that understanding this theory necessitates a grasp of sophisticated quantum mechanics, as it is fundamentally rooted in quantum processes.

PREREQUISITES
  • Understanding of Cooper pairs and their role in superconductivity
  • Familiarity with bosons and fermions in quantum mechanics
  • Knowledge of the Pauli exclusion principle
  • Basic concepts of electrical resistance and conductivity
NEXT STEPS
  • Research the properties of Cooper pairs in superconductors
  • Study the implications of bosonic behavior in quantum mechanics
  • Explore the relationship between superconductivity and diamagnetism
  • Investigate the mathematical framework of quantum mechanics relevant to superconductivity
USEFUL FOR

Physicists, materials scientists, and students of quantum mechanics seeking to understand the fundamental principles of superconductivity without delving into complex quantum theories.

welatiger
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hello everybody
i want informational about microscopic theory of superconductivity but without sophisticated quantum mechanics
can you help me ?
 
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the electrons form 'cooper pairs'. somehow that results in virtually zero resistance
 


Not virtually zero, but actually zero resistance.

The Cooper pair is a quasiparticle. Unlike the two electrons inside it, the Cooper pair is a Boson, not a Fermion. Therefore the Cooper pair is not limited by the Pauli exclusion principle and all the Cooper pair are in the ground state (lowest quantum numbers).

In the case of a free electron (Fermion) conductivity requires electrons to be in excited states because they are above the Fermi energy so scattering of the excited electrons drops them back into the ground state. For the Boson there is no such scattering process.
 


welatiger said:
hello everybody
i want informational about microscopic theory of superconductivity but without sophisticated quantum mechanics
can you help me ?

No. The microscopic theory requires "sophisticated quantum mechanics". This is fundamentally a quantum mechanical process.
 


do the cooper pairs form a degenerate gas?
 

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