Min force to open the water gate

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SUMMARY

The discussion centers on the calculation of the force required to open a water gate, specifically addressing the equation Fr(Lp) = FB / 2. Participants clarify that the force FB acts on one side of the gate at a distance b/2 from the hinge, leading to the conclusion that Fr must be evaluated at Lp from the hinge on the opposite side. The conversation also critiques the diagram provided in the homework statement for its lack of clarity regarding the hinge and the representation of the water surface.

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Homework Statement


why Fr(Lp) = FB / 2 ? can someone help to explain ?

Homework Equations

The Attempt at a Solution


shouldn't it be 2FB = Fr(Lp) ? since FB act on 2 sides of the gate ...[/B]
 

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It's Fb/2 because F acts at b/2 from the hinge. It only acts on one side.
Fr acts at Lp from the hinge on the other side.
 
Author sure has a funny way of drawing a 45 degree angle !
And conspicuously does not draw a hint of a hinge at B.

Furthermore, the horizontal line at 3 m is supposed to designate something sturdy that has water above and air below ? Quite something different from the liquid surface at 4.2 m; more like the stuff the gate itself should be made of. Deceptive drawing, incompetence, sloppiness ?
 

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