Min max: optimal quantity of medicine

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SUMMARY

The discussion focuses on finding the optimal quantity of medicine by analyzing the first derivative of the revenue function, R(D). The key equation derived is $$R' = 2D\left( \frac{C}{2}-\frac{D}{3} \right)-\frac{1}{3}D^2$$, which is set to zero to find critical points. Participants emphasize the importance of differentiating between maximizing R'(D) and R(D), clarifying that the maximum of R' indicates where small changes in D significantly affect R. A recommendation is made to substitute numerical values for C and plot R(D) and R'(D) for better understanding.

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Homework Statement


Capture.JPG


Homework Equations


Minimum/Maximum occurs when the first derivative=0

The Attempt at a Solution


$$R'=2D\left( \frac{C}{2}-\frac{D}{3} \right)-\frac{1}{3}D^2$$
$$R'=0~\rightarrow~D=C$$
 

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Karol said:

Homework Statement


View attachment 230882

Homework Equations


Minimum/Maximum occurs when the first derivative=0

The Attempt at a Solution


$$R'=2D\left( \frac{C}{2}-\frac{D}{3} \right)-\frac{1}{3}D^2$$
$$R'=0~\rightarrow~D=C$$
Read carefully.
upload_2018-9-19_15-45-13.png


It discusses the point where ##\ R^\prime (D) \ ## is a maximum, not about the max of ## R(D)\,.##

Also, it may help to write R(D) as: ##\ \displaystyle R(D) = \frac{D^2C}{2}-\frac{D^3}{3} \,.##

.
 

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$$R'=2D\left( \frac{C}{2}-\frac{D}{3} \right)-\frac{1}{3}D^2,~~R''=C-2D,~~R''=0:~D=\frac{C}{2}$$
But the greatest change in R for a small change in D is where R has a maximum, hence where R'=0, not where R''=0
 
Karol said:
$$R'=2D\left( \frac{C}{2}-\frac{D}{3} \right)-\frac{1}{3}D^2,~~R''=C-2D,~~R''=0:~D=\frac{C}{2}$$
But the greatest change in R for a small change in D is where R has a maximum, hence where R'=0, not where R''=0
Read the problem again. It's R'(D) which you need to find the maximum for, not finding the maximum for R(D) .
 
Yes, that's correct, i need the maximum for R', but why?
At the point where R has a maximum, i think, a small change in D makes a big change in R
 
Karol said:
Yes, that's correct, i need the maximum for R', but why?
At the point where R has a maximum, i think, a small change in D makes a big change in R

No, that's where R' is a maximum. R' = 0 is where there is no change with a change in D.
 
Karol said:
Yes, that's correct, i need the maximum for R', but why?
At the point where R has a maximum, i think, a small change in D makes a big change in R

No: at the maximum a small change in ##D## makes NO change in ##R##! The tangent line to the graph ##R = f(D)## is horizontal at an interior maximum; that is why we look for points where the derivative vanishes when maximizing or minimizing.

You really need to have a better intuitive understanding of this material, and to help with that I suggest that you substitute some numerical value for ##C##, then plot ##R(D)## and ##R'(D)##.
 
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