Min max using partial derivatives

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SUMMARY

The discussion focuses on finding critical points for the function (x^2 + y^2)e^(y^2 - x^2) using partial derivatives. The first derivatives are established as Fx=2xe^(y^2-x^2)(1-x^2-y^2) and Fy=2ye^(y^2 - x^2)(1+x^2+y^2). Critical points occur when Fx=0 or Fy=0, leading to solutions at (0, 0), (1, 0), and (-1, 0), with the unit circle defined by x^2 + y^2 = 1 being a significant condition for Fx=0.

PREREQUISITES
  • Understanding of partial derivatives
  • Familiarity with critical point analysis
  • Knowledge of exponential functions
  • Basic concepts of multivariable calculus
NEXT STEPS
  • Study the method of Lagrange multipliers for constrained optimization
  • Learn about the Hessian matrix for classifying critical points
  • Explore the implications of critical points in multivariable functions
  • Investigate the behavior of functions on the unit circle
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Students and professionals in mathematics, particularly those studying calculus, optimization techniques, and multivariable functions.

StephenDoty
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(x^2 + y^2)*e^(y^2 - x^2)
I am having trouble finding the critical points.

Fx=2xe^(y^2-x^2)(1-x^2-y^2)=0
Fy=2ye^(y^2 - x^2)(1+x^2 +y^2)=0

or
0=x(1-x^2-y^2)
0=y(1+x^2+y^2)

now, finding all the roots is giving me trouble. x and y obviously = 0, but I am unsure how to move forward to get the rest of the zeros, therefore giving me the critical points. Any help would be appreciated. Thanks.

Stephen
 
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Fx = 0 iff x = 0 or x^2 + y^2 = 1
That is, Fx = 0 when x = 0 or when (x, y) is a point on the unit circle centered at (0, 0).

Fy = 0 iff y = 0 (1 + x^2 + y^2 >= 1 for all real (x, y) )
So both partials are 0 simultaneously for (0, 0), (1, 0), or (-1, 0).
 

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