Minimize Tension of Mass m Hanging from Cords

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Homework Help Overview

The problem involves a mass m hanging from two cords, with one cord attached to the wall and the other to the ceiling, forming angles with the horizontal. The objective is to determine the angle theta that minimizes the tension in the second cord and to express this minimum tension in terms of mg.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss using a force diagram and consider different methods such as vector triangles and component analysis. There is an exploration of relationships between the tensions in the cords based on their angles and components.

Discussion Status

Some participants have provided guidance on methods to approach the problem, while others are questioning assumptions made in the reasoning process. There is an ongoing exploration of the relationships between the tensions and angles without a clear consensus on the correctness of the assumptions.

Contextual Notes

Participants are navigating through the constraints of the problem, including the need to minimize tension and the implications of angle choices. There is an acknowledgment of the complexity involved in eliminating variables and minimizing expressions.

munchy35
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Homework Statement



A package of mass m hangs from a short cord that is tied to the wall via cord 1 and to the ceiling via cord 2. Cord 1 is at angle 40 degrees with the horizontal; cord 2 is at angle, theta.

a) for what value of theta is the tension in cord 2 minimized?
b)in terms of mg, what is the minimum tension in cord 2?

(here's the link of the problem with the picture http://www.unc.edu/~rowan/phys26/P26recit/p26-12-b.htm )

I know I have to figure out the force diagram first. I'm just having trouble with where to start.

I'm not asking for the solution, i just need some direction,
 
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Hi munchy35! :wink:

You can solve this either with a vector triangle, or by taking components in a convenient direction.

Choose one method, and show us how far you get. :smile:
 
i used the component method so

for horizontal component i said t1cos40=t2cosx

(i'm just using x for theta)

t2=t1cos40/cosx

and t1 = t2cosx/cos40

so for part a, i used the t2 equation and just assumed for t2 to be a minimum cos x had to be maximum, the maximum cosx=1, so x= 0 degrees

^ can i just assume that?

for part b, i used vertical component

t1sin40 + t2sinx = mg

after plugging in t1

t2 = mg/ tan40cos0 + sin0

and eventually get 1.192mg

is that right
 
Hi munchy35! :smile:
munchy35 said:
… for horizontal component i said t1cos40=t2cosx

t1sin40 + t2sinx = mg

so for part a, i used the t2 equation and just assumed for t2 to be a minimum cos x had to be maximum, the maximum cosx=1, so x= 0 degrees

^ can i just assume that?

Nooo … stop trying to take short-cuts! :rolleyes:

Your two equations are correct :smile:

now eliminate t1 to find t2 …

then minimise t2. :wink:
 

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