Minimizing by trisecting a function dependent on 3 parameters

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Discussion Overview

The discussion revolves around the minimization of a function dependent on three parameters, one of which is nonlinear. Participants are exploring the process of minimizing this function through a method involving trisection of an interval, as suggested by a referenced document. The conversation includes confusion regarding the treatment of multiple parameters during this minimization process.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant expresses confusion about how to minimize a function by trisection while focusing on just one parameter, questioning the role of the other parameters.
  • Another participant suggests an iterative approach involving setting a range for the nonlinear parameter, trisecting it, and using "robust linear estimation" to find corresponding values for other parameters.
  • The same participant proposes a discarding rule based on the values obtained from the trisection, but acknowledges uncertainty about the necessity of the first function after obtaining values for the parameters.
  • A later reply clarifies that certain terms in the equation do not depend on specific parameters, but does not resolve the overall confusion regarding the functions involved.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the method of minimizing the function or the roles of the different parameters. Multiple competing views and uncertainties remain regarding the approach to take.

Contextual Notes

Participants express uncertainty about the definitions and roles of certain variables and functions mentioned in the referenced document, which may affect their understanding of the minimization process.

borson
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Hi and thanks to everyone for his/her attention. I have to minimize a function that depends on several parameters. The aim of minimizing that function is to actually guess these parameters, which are unknown. The thing is that the author of the pdf from which I have to make the calculations, does not specify very well how to carry it out. There are 3 parameters the function depends on (one of them nonlinear), and the author says that first off we have to figure out the nonlinear parameter, by trisecting a determined interval, and afterwards guess the spare ones by means of another function that will also have to be minimized. So here is where I am confused. How am I supossed to minimize a function by trisection paying attention to just one parameter? I mean, what do I have to do with the other ones? How should I do it?

Here is the part of the pdf in which that function is shown:

you can find the whole pdf here:http://www.roulettephysics.com/wp-content/uploads/2014/01/Roulette_Physik.pdf

that function is in the 13 page.

thank you all for your attention and I hope you can help me :)
 
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borson said:
Hi and thanks to everyone for his/her attention. I have to minimize a function that depends on several parameters. The aim of minimizing that function is to actually guess these parameters, which are unknown. The thing is that the author of the pdf from which I have to make the calculations, does not specify very well how to carry it out. There are 3 parameters the function depends on (one of them nonlinear), and the author says that first off we have to figure out the nonlinear parameter, by trisecting a determined interval, and afterwards guess the spare ones by means of another function that will also have to be minimized. So here is where I am confused. How am I supossed to minimize a function by trisection paying attention to just one parameter? I mean, what do I have to do with the other ones? How should I do it?

Here is the part of the pdf in which that function is shown:

you can find the whole pdf here:http://www.roulettephysics.com/wp-content/uploads/2014/01/Roulette_Physik.pdf

that function is in the 13 page.

thank you all for your attention and I hope you can help me :)
Not sure, but I think the idea is to iterate as follows:
  1. set the range [φmin, φmax] for φ as [0, 2π]
  2. trisect the range, i.e. consider values φmin, 2φmin/3+ φmax/3, φmin/3+2φmax/3, φmax for φ
  3. for each of the four values, v1 to v4, use "robust linear estimation" (whatever that is) to find the corresponding η and Ω2f;
  4. discard the first or last third of the range for φ which appears not to be promising; this assumes the behaviour is not too jerky
  5. repeat from 2.
The discarding rule, I guess, would be
if f(v2)<f(v3) discard [v3, v4], else discard [v1, v2].
 
haruspex said:
Not sure, but I think the idea is to iterate as follows:
  1. set the range [φmin, φmax] for φ as [0, 2π]
  2. trisect the range, i.e. consider values φmin, 2φmin/3+ φmax/3, φmin/3+2φmax/3, φmax for φ
  3. for each of the four values, v1 to v4, use "robust linear estimation" (whatever that is) to find the corresponding η and Ω2f;
  4. discard the first or last third of the range for φ which appears not to be promising; this assumes the behaviour is not too jerky
  5. repeat from 2.
The discarding rule, I guess, would be
if f(v2)<f(v3) discard [v3, v4], else discard [v1, v2].

It seems a good idea.
I will try to do that, though I do not understand the last function either. I do not have any idea of what the yk and the xk stand for.
Also, considering the discarding rule, regarding what you have said, it seems that I only need the second function for discarding. So then, why is the first function for?
At the beginning I am obliged to use the f(v) of the second function (as I do not have any guess of the linear parameters to use in the first one yet), to see which set of values for the parameters yield the most minimum value, but once I do that and by means of that I obtain values for that parameters, should I keep using the second function for discardingn or the first one?
Thanks for replying :)
 
borson said:
I do not have any idea of what the yk and the xk stand for.
These just stand for terms in the equation at (42) which do not depend on η or Ω. So yk=c1e-2aθfk and xk represents everything inside the square brackets.
 

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