Minimum force necessary to push out a cork

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SUMMARY

The minimum force required to push out a cork from a U-tube with differing diameters is determined by the pressure equations applied to each arm. Given that a force of 16N is needed to remove the cork from the narrow arm, the calculations show that the force needed at the piston in the wider arm is 64N. The error in the initial calculation stemmed from incorrectly applying the area formula for the wider arm, specifically miscalculating the area as π*2r² instead of the correct π*(2r)².

PREREQUISITES
  • Understanding of fluid mechanics principles
  • Familiarity with pressure calculations (p = F/A)
  • Knowledge of U-tube configurations
  • Basic algebra for manipulating equations
NEXT STEPS
  • Study the principles of hydrostatic pressure in fluids
  • Learn about Pascal's law and its applications in fluid systems
  • Explore dimensional analysis techniques for problem-solving
  • Investigate the effects of varying cross-sectional areas on fluid dynamics
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Students studying physics, particularly those focusing on fluid mechanics, as well as educators looking for practical examples of pressure calculations in U-tube systems.

drunknfox
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Homework Statement


2 arms of a u-tube are not identical, one having twice the diameter of the other. a cork in the narrow arm requires a force of 16n to remove it. the tube is filled with water and the wide arm is fitted with a piston. the min force that must be applied to the piston to push out cork is?


Homework Equations


p=f/a


The Attempt at a Solution


p1=f1/(pi*r^2), p2=f/pi*2r^2, p1=p2, f1/(pi*r^2)=f2/(pi*2r^2)...f2=(pi*r^2)*f1/(pi*r^2) which gives me 32. The answer is actually 64. What am i missing?
 
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hi drunknfox! :smile:

(have a pi: π and try using the X2 icon just above the Reply box :wink:)
drunknfox said:
p1=f1/(pi*r^2), p2=f/pi*2r^2, p1=p2, f1/(pi*r^2)=f2/(pi*2r^2)...f2=(pi*r^2)*f1/(pi*r^2) which gives me 32. The answer is actually 64. What am i missing?

it isn't π*2r2 :redface:

(and using a dimensional argument would be much quicker, and less likely to lead to a mistake)
 

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