Minimum Wire Length Calculation for Square Pattern in 10cm Square

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The discussion revolves around calculating the minimum wire length for a horizontal line segment, \(x\), within a 10 cm square, connecting to the closest corners. The total wire length is expressed as \(l = x + 4y\), where \(y\) is derived using the Pythagorean theorem. There is confusion regarding whether the problem asks for the minimum value of \(x\) or the value that minimizes the total length \(l\). Participants emphasize the importance of confidence in problem-solving methods and the potential for errors in the learning process. The problem's wording is questioned, particularly the feasibility of setting \(x = 0\).
squenshl
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Homework Statement


A wire pattern is inserted into a ##10##cm square by making a horizontal line in the middle of the square (not all the way across and with length ##x##) and connecting the ends of this line to the closest two corners. What is the minimum value of ##x##?

Homework Equations

The Attempt at a Solution


Let ##y## be the length of the wire from the end of ##x## to the corner of the square. This means the total length of the wire is ##l = x+4y##.

I extended the blue line ##x## to create a triangle then I used Pythagoras' to get ##y^2 = 25+\frac{(10-x)^2}{4}##.

Do I then throw this (meaning ##y##) into ##l## then differentiate with respect to ##x## then solve to get my minimum value for ##x## then ##y## which would give me the minimum length for ##l##.

Thanks!
 

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squenshl said:

Homework Statement


A wire pattern is inserted into a ##10##cm square by making a horizontal line in the middle of the square (not all the way across and with length ##x##) and connecting the ends of this line to the closest two corners. What is the minimum value of ##x##?

Homework Equations

The Attempt at a Solution


Let ##y## be the length of the wire from the end of ##x## to the corner of the square. This means the total length of the wire is ##l = x+4y##.

I extended the blue line ##x## to create a triangle then I used Pythagoras' to get ##y^2 = 25+\frac{(10-x)^2}{4}##.

Do I then throw this (meaning ##y##) into ##l## then differentiate with respect to ##x## then solve to get my minimum value for ##x## then ##y## which would give me the minimum length for ##l##.

Thanks!

If that is what you think you should do, why ask us? Just do it!

The point is that you need to start having confidence in your own methods, and you need to be willing to make a mistake, perhaps spending a lot of time on an erroneous approach, then throwing out the worksheets and starting again. That is how all of the homework helpers learned the subject!
 
The problem statements seems to be ill at least to me. The problem asks for the minimum value of ##x ##(which if understand correctly is the length of the segment in the middle of square). What prevents us from taking ##x=0##?
The only thing I can make is that you probably meant to say the value of ##x## that minimizes the total length ##l## cause that's what your method calculates.
 
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Delta2 said:
The problem statements seems to be ill at least to me. The problem asks for the minimum value of ##x ##(which if understand correctly is the length of the segment in the middle of square). What prevents us from taking ##x=0##?
The only thing I can make is that you probably meant to say the value of ##x## that minimizes the total length ##l## cause that's what your method calculates.
what he said (very small).jpg
 

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Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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