(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Object A of mass 10 kg moving at 10 m/s [E] interacts with (but does not touch) Object B of mass 8 kg moving at 12 m/s [N]. What is the minimum possible kinetic energy of the system after the collision?

2. Relevant equations

M_{1}V_{1o}+ M_{2}V_{2o}= M_{1}V_{1f}+ M_{2}V_{2f}

KE = (.5)(m)(v^{2})

Kinetic energy is minimized in a completely inelastic collision.

3. The attempt at a solution

10(10) + 8(12) = (10 + 8)v

v = 10.89 m/s

KE = (.5)(10)(10.89)^{2}+ (.5)(8)(10.89)^{2}

KE = 1067 J

Correct answer: 534 J (which is one-half of the answer I got.)

Help please?

Thanks.

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# Homework Help: Minimum possible kinetic energy in an interaction

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